Helpppppppppppppppppppppp

Multiply. (give answer as a mixed number.) 6 1/4 x 3 3/5 =

sladkih [1.3K]

Okay, I went through a lot of work to try solving this, so here goes! First, turn the mixed numbers into improper fractions. 6 1/4 --> 25/4 3 3/5 --> 18/5 Next, we need to multiply the two improper fractions together. 25 x 18 450 --- --- = --- 4 x 5 20 Then, we need to turn 450/20 into a mixed number. To do this, we divide. 450/20=22 10/26 We're almost done. Last step is to simplify the mixed number, specifically 10/26. We need to find GCF of 10 and 26, which is 2. 10/2=5 26/2=13 = 5/13 FINAL ANSWER - 22 5/13 You're welcome.

3 0

4 years ago

Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Is this possible if he invests with a rate

Juli2301 [7.4K]

Pablo has $4,200 to invest for college. Pablo's goal is to have $5,000 after 4 years. Question: Is this possible if he invests with a rate of return of 6%?We'll we are not sure with the answer unless we solve it. So let's start solving.=> 6% = 6% / 100% = 0.06Now, we have the value of 6% that will be multiplied with the amount to identify his annual interest rate:=> $4,200 * 0.06 = 252 dollars is his annual interest rateLet's multiply this for 4 years=> 252 dollars * 4 = 1008 dollarsThen, let's sum up:<span>=> $4,200 + 1008 dollars = 5 208 dollars.</span>

5 0

3 years ago

Read 2 more answers

HELP MEEHHHHHHHHHHHHH.<br>

lilavasa [31]

Answer:

i think it is 15,840 because if you multiply 3 by 5,280 you will get 15,840

Step-by-step explanation:

6 0

3 years ago

Write the slope intercept form of 11x-8y=-48

bija089 [108]

Y=(11/8)x+6
subtract the 8y to the right then add the 48 to the left then divide by 8

8 0

4 years ago

Integrated circuits consist of electric channels that are etched onto silicon wafers. A certain proportion of circuits are defec

boyakko [2]

Answer:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

Step-by-step explanation:

1) Data given and notation

n=1000 represent the random sample taken

X=33 represent the number of circuits that show evidence of undercutting

$\hat p=\frac{33}{1000}=0.033$ estimated proportion of circuits that show evidence of undercutting

$p_o=0.05$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that they reduce the rate of undercutting to less than 5%.:

Null hypothesis: $p\geq 0.05$

Alternative hypothesis: $p < 0.05$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.033 -0.05}{\sqrt{\frac{0.05(1-0.05)}{1000}}}=-2.467$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z>-2.467)=0.0068$

So the p value obtained was a very low value and using the significance level assumed for example $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of circuits that show evidence of undercutting is significantly less than 0.05.

4 0

3 years ago