You're given a table of x values and an equation. To solve, plug in the values for x.
First box: y=2(-3)-1=-7
Second box: y=2(-2)-1=-5.
See if you can solve the third one.
1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve
Here is an example:
4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.
<span>Hope that helps</span>
Answer:

Step-by-step explanation:
Starting from the y-intercept of
you do
by either moving four blocks <em>south</em><em> </em>over one block <em>west</em><em> </em>or four blocks <em>north</em><em> </em>over one block<em> east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be <em>less</em><em> </em><em>than</em><em> </em>and <em>greater</em><em> </em><em>than</em><em> </em>since this is a <em>dashed</em><em> </em><em>line</em><em> </em>graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:
<em>Greater</em><em> </em><em>than</em>
☑
<em>Less</em><em> </em><em>than</em><em> </em>
![\displaystyle 0 < 4[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%204%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
This graph is shaded in the portion of the origin, so you would choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality symbol to get this inequality:

I am joyous to assist you anytime.
F(2)=8 and f(5v)=25v^2+15v-2
Answer:
43
Step-by-step explanation:
43 is a prime number