Question

Which shows the expression x^2-1/x^2-x in simplest form

Answer 1

Answer: B

Step-by-step explanation:

Answer 2

Answer:

$\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}$

Step-by-step explanation:

$\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}$