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Studentka2010 [4]
2 years ago
15

Please help with these 2 questions :(( I really will appreciate it a lot

Mathematics
1 answer:
Art [367]2 years ago
4 0

Answer:

c

Step-by-step explanation

DO NOT  CHANGE YOU ANSWER. it is perfectly fine

pls mark brainliest

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What is the answer for the four at the bottom?
Sladkaya [172]
What am I suppose to do so I can help you?
7 0
2 years ago
Given ΔMNO, find the measure of ∠LMN.
Novay_Z [31]

Answer:

  104°

Step-by-step explanation:

If segments NO and NM are congruent, then angles NMO and NOM are congruent. So, their supplements, angles NML and NOP are congruent. That is ...

  ∠NML ≅ ∠NOP = 104°

  ∠NML = 104°

3 0
2 years ago
Read 2 more answers
What is the value of x?
Orlov [11]

Answer:

x = 24.5

Step-by-step explanation:

There are two similar triangles. In similar triangles the sides are in proportion.

Let's name big triangle as triangle 1 and small triangle as triangle 2.

The sides of the big triangle:

27 as base and the longest side (x + 7)

The sides of the small triangle:

base = 27 - 6 = 21

longest side = x

We need to find the value of x using proportion.

27/21 = (x + 7)/ x

By cross multiplying, we get

27(x) = 21(x + 7)

27x = 21x + 147

27x - 21x = 147

6x = 147

Dividing both sides by 6, we get

x = 147/6

x = 24.5

The value of x = 24.5

Hope you will understand the concept.

Thank you.

5 0
2 years ago
Why is the number of operators per shift multiplied by approximately 4.5 to obtain the total number of operators required to run
4vir4ik [10]

I believe you meant "why is the number of shifts multiplied by approximately 4.5 to obtain the total number of operators required to run the plant"

Answer and Explanation:

There are 3 shifts per day, 49 weeks per year and 5 shifts per operator per week

To get total number of operators required to run the plant, we multiply number of shifts in a year by number if operators per shift.

49 weeks×5 shifts= 245 shifts per operator per year

365×3 shifts= 1095 shifts per year

1095/245=4.5 operators per shift

total number of operators required to run the plant(per day) = 4.5×3= 13.5 approximately 14

total number of operators required to run the plant(per year) =4.5×1095=4927.5 approximately 4928

3 0
3 years ago
In the video, the water level was 15 milliliters before adding the chain, and 20 milliliters after adding the chain. When I weig
mr_godi [17]

Answer:

  • 39.7%

Explanation:

<u />

<u>1. First find the density of your chain</u>

  • Density = mass / volume

  • Volume = displaced water volume

                      = Volume of Final level of water - initial level of water

                     = 20 ml - 15 ml = 5 ml

  • Mass = 66.7 g

  • Density = 66.7g / 5 ml = 13.34 g/ml

<u />

<u>2. Second, write the denisty of the chain as the weighted average of the densities of the other metals:</u>

Mass of gold × density of gold + mass of other metals × density of other metals, all divided by the mass of the chain.

Calling x the amount of gold, then the amount of other metals is 66.7 - x:

        \dfrac{19.3\cdot x+9.7\cdot (66.7-x)}{66.7}=13.34

       19.3x+635.66-9.7x=889.778

      9.6x=254.118\\\\x=26.47

Then, there are 26.47 grams of gold in 66.7 grams of chain, which yields a percentage of:

  • (26.47 / 66.7) × 100 = 39.7%
7 0
3 years ago
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