Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer:
it's 270! the formula for triangles is base times height divided by 2, the measurement on the side means nothing in context of finding area
5g is bigger then 4,000mg
Answer:
X = -2
y = 2
Step-by-step explanation:
Substitute y=x + 4 in the second equation to find x
x+4 = 2x + 6
subtract x from both sides
4 = x + 6
subtract 6 from both sides
-2 = x
put -2 in for x in the first equation
y= 2
Answer:
x = 8
Step-by-step explanation:
Step 1: Write equation
-5 + x = 3
Step 2: Solve for <em>x</em>
- Add 5 to both sides: x = 8
Step 3: Check
<em>Plug in x to verify it's a solution.</em>
-5 + 8 = 3
3 = 3
