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Vesnalui [34]
3 years ago
5

10 points ??????????????

Mathematics
1 answer:
drek231 [11]3 years ago
7 0

Answer:

I would think it would be D if im correct

Step-by-step explanation:

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A mass of 1 g is set in motion from its equilibrium position with an initial velocity of 6in/sec, with no damping and a spring c
yan [13]

a) y(t)=0.0016 sin(94.9t) [m]

b) 0.033 s

c) -0.152 m/s

Step-by-step explanation:

a)

The force acting on the mass-spring system is (restoring force)

F=-ky

where

k = 9 is the spring constant

y is the displacement

Also, from Newton's second law of motion, we know that

F=my''

where

m = 1 g = 0.001 kg is the mass

y'' is the acceleration

Combining the two equations,

my''=-ky

This is a second order differential equation; the solution for y(t) is

y(t)=A sin(\omega t-\phi)

where

A is the amplitude of motion

\omega=\sqrt{\frac{k}{m}}=\sqrt{\frac{9}{0.001}}=94.9 rad/s is the angular frequency

The spring starts its motion from its equilibrium position, this means that y=0 when t=0; therefore, the phase shift must be

\phi=0

So the displacement is

y(t)=A sin(\omega t)

The velocity of the spring is equal to the derivative of the displacement:

v(t)=y'(t)=\omega A cos(\omega t)

We know that at t = 0, the initial velocity is 6 in/s; since 1 in = 2.54 cm = 0.0254 m,

v_0=6(0.0254)=0.152 m/s

And since at t = 0, cos(\omega t)=1

Then we have:

v_0=\omega A

From which we find the amplitude:

A=\frac{v_0}{\omega}=\frac{0.152}{94.9}=0.0016 m

So the solution for the displacement is

y(t)=0.0016 sin(94.9t) [m]

b)

Here we want to find the time t at which the mass returns to equilibrium, so the time t at which

y=0

This means that

sin(\omega t)=0

We know already that the first time at which this occurs is

t = 0

Which is the beginning of the motion.

The next occurence of y = 0 is instead when

\omega t = \pi

which means:

t=\frac{\pi}{\omega}=\frac{\pi}{94.9}=0.033 s

c)

As said in part a), the velocity of the mass-spring system at time t is given by the derivative of the displacement, so

v(t)=\omega A cos(\omega t)

where we have

\omega=94.9 rad/s is the angular frequency

A=0.0016 m is the amplitude of motion

t is the time

Here we want to find the velocity of the mass when the time is that calculated in part b):

t = 0.033 s

Substituting into the equation, we find:

v(0.033)=(94.9)(0.0016)cos(94.9\cdot 0.033)=-0.152 m/s

4 0
3 years ago
SOMEONE PLEASE HELP 100 POINTS AND BRAINLIEST AND 5 STAR RATING! PLEASE HELP! :)
weqwewe [10]

1 cm            3 cm

---------   =  ---------

3 in               x inches


The ratio has to stay in the same order  cm on top, inches on the bottom


Choice C

4 0
3 years ago
What is the inverse of f(x)=4x
Allisa [31]
The sum can be rewritten as y=4x, where y=f(x).
Now, we can rewrite the equation a x=y/4
Therefore, inv(f(x))=x/4
3 0
3 years ago
Read 2 more answers
Brooke plays on her schools softball team. Last season she was at bat 500 times and made a safe hit 28% of the time. How is 28%
Gre4nikov [31]

Answer:

28/100

Step-by-step explanation:

5 0
2 years ago
Can you exchange the coordinates of points ( x 1, y 1) and ( x 2, y 2) in the distance formula and still find the correct distan
notka56 [123]

Answer:

yes

Step-by-step explanation:

As an example

(x₁, y₁ ) = (1,2) and (x₂, y₂ ) = (5,3), then

d = \sqrt{(5-1)^2+(3-2)^2} = \sqrt{4^2+1^2} = \sqrt{16+1} = \sqrt{17}

Now let (x₁, y₁ ) = (5,3) and (x₂, y₂ ) = (1,2), then

d = \sqrt{(1-5)^2+(2-3)^2} = \sqrt{(-4)^2+(-1)^2} = \sqrt{16+1} = \sqrt{17}


3 0
3 years ago
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