PLEASE HELP ASAP I NEED THIS PLEASEEEEEE I ONLY HAVE 20 POINTS AND IM USING THEM ALL FOR THIS PLEASE HELP ME I WILL GIVE YOU BRA
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2 answers:
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Answer:
Step-by-step explanation:
Given that a small manufacturing firm has 250 employees. Fifty have been employed for less than 5 years and 125 have been with the company for over 10 years. So remaining 75 are between 5 and 10 years.
Suppose that one employee is selected at random from a list of the employees
A) Probability that the selected employee has been with the firm less than 5 years =
B) Probability that the selected employee has been with the firm between 5 and 10 years
=
C) Probability that the selected employee has been with the firm more than 10 years
=
a) P(A) = 0.2
P(C) = 0.5
P(A or B) = 0.2+0.3 = 0.5
P(A and C) = 0 (since A and C are disjoint)
Answer:
The probability is 0.003
Step-by-step explanation:
We know that the average is:
The standard deviation is:
The Z-score is:
We seek to find
For P(x>800) The Z-score is:
The score of Z = 3 means that 800 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So
For P(x<200) The Z-score is:
The score of Z = -3 means that 200 is 3 standard deviations from the mean. Then by the rule of the 8 parts of the normal curve, the area that satisfies the conficion of 3 deviations from the mean has percentage of 0.15%
So
Therefore