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FrozenT [24]
3 years ago
9

Can someone please help a lady out ASAP? please and Thankyou. I will give you crown

Mathematics
1 answer:
gtnhenbr [62]3 years ago
8 0
I hope it’s right?! You just need to do this

You might be interested in
Write a quadratic function f whose zeros are 3 and 10
Anettt [7]

Answer:

f(x) =  {x}^{2}  - 13x + 30

Step-by-step explanation:

A quadratic equation may be expressed as a product of the two binomials. The roots of the equations are 3 and 10, so the factors are (x-3) and (x-10).

f(x) = (x-3)(x-10)

f(x) = x^2 - 13x + 30

4 0
3 years ago
Plzzzzzzz help
kherson [118]
Answer: Function h(x)

==========================================================

Explanation:

To compare the average rate of change (AROC) for the three functions, we'll use the formula

AROC = (p(a) - p(b))/(a-b)

where p(x) is any general function and [a,b] is the interval we care about. In this case, a = 2 and b = 4.

For f(x), we have
f(x) = (-5/2)*(3)^x
f(2) = (-5/2)*(3)^2
f(2) = -22.5
--------
f(x) = (-5/2)*(3)^x
f(4) = (-5/2)*(3)^4
f(4) = -202.5
--------
AROC = (f(a)-f(b))/(a-b)
AROC = (f(2)-f(4))/(2-4)
AROC = (-22.5-(-202.5))/(2-4)
AROC = -90
So we can rule out function f as the AROC here is -90 but we want the AROC to be -6

For g(x) we have
AROC = (g(a)-g(b))/(a-b)
AROC = (g(2)-g(4))/(2-4)
AROC = (-5-(-77))/(2-4)
AROC = -36
So we can rule out g(x) as well

For h(x) we have
AROC = (h(a)-h(b))/(a-b)
AROC = (h(2)-h(4))/(2-4)
AROC = (0-(-12))/(2-4)
AROC = -6
h(x) is the function that has the proper AROC we want

So that's why h(x) is the only answer
7 0
4 years ago
Expand each expression and collect like terms. a. -3(2p - 3q) <br>​
emmasim [6.3K]

Answer:

-6p+9q

Step-by-step explanation:

Multiply -3 with 2p and multiply -3 with 3q.

8 0
3 years ago
Make a the subject of the formula:p=2a-3
IceJOKER [234]
To make a the subject we proceed as follows:
p=2a-3
add 3 on both sides
3+p=2a-3+3
simplifying the above gives us:
3+p=2a
divide both through  by 2
3/2+p/2=(2a)/2
thus
a=3/2+p/2
5 0
3 years ago
Of all rectangles with a perimeter of 7​, which one has the maximum​ area? (give the​ dimensions.)
Elena L [17]
The rectangle with maximum area will actually be a square.

Each side will be of length  7/4 = 1 3/4.
3 0
3 years ago
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