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Katena32 [7]
3 years ago
12

Urgent!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
sasho [114]3 years ago
8 0

Answer:

Since we don't know the length of sides PR and XZ, the triangles can't be congruent by the SSS theorem or the SAS theorem, and since we don't know the measure of angles Y and Q, the triangles can't be congruent by the ASA theorem, the SAS theorem or the AAS theorem. Therefore, Carlos is correct.

Step-by-step explanation:



Anna35 [415]3 years ago
6 0

Answer:

<h2>Carlos is Correct</h2>

Step-by-step explanation:

Carlos is correct. Since the angles P and X are not included between PQ and RQ and XY and YZ, the SAS postulate cannot be used, since it states that the angle must be included between the sides. Unlike with ASA, where there is the AAS theorem for non-included sides, there is not SSA theorem for non-included angles, so the triangles cannot be proven to be congruent.

<h3>___________________________________________________</h3><h3><em>I AM ALWAYS HAPPY TO HELP :)</em></h3>
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Help me out please an thank you
Hunter-Best [27]

Answer:

equivalent is the aswer

5 0
3 years ago
Read 2 more answers
A circle is cut from a square piece of cloth, as shown: A square, one side labeled as 42 inches has a circle inside it. The circ
olasank [31]

Answer:

\huge\boxed{\sf Area\ of\ the\ circle = 1385.4\ in.\²}

Step-by-step explanation:

We have to find out the area of the square in order to find how many square inches were cut from the squared cloth.

Diameter = 42 in.

Radius = D / 2 = 42 / 2 = 21 in.

Area of circle = πr²

Where r = 21 in.

Area = (3.14)(21)²

Area = (3.14)(441)

Area of the circle = 1385.4 in.²

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>

3 0
3 years ago
Read 2 more answers
HI MATHS EXPERTS PLS ANSWER ASAP PLS I AM DESPERATE
katovenus [111]

c. 2310 (1st pic)

circumference of circle = 2πr

44= 2 × 22/7 r

44 × 7 / (2 × 22) = r

7 = r

volume of cylinder = πr^2h

= 22/7 × (7)^2 ×15

= 2310

b. -2/x+3 (2nd pic)

(work attached)

a. 80° (3rd pic)

Total number of degrees is 180

180-(60+40)=80

c. 9 (5th pic)

(27^1/3)^2

3^2

=9

sorry i couldn't solve the 4th pic but I hope this helps!

please mark me brainliest!

3 0
3 years ago
Jim’s gas credit card bill was $80.97 for June, $41.35 for July and $65.08 for August. What were his total charges for summer?
ruslelena [56]

Answer: Jim’s gas credit card bill was $187.4 for summer?

Step-by-step explanation:

80.97+ 41.35+65.08=187.4

the answer is $187.4

7 0
2 years ago
A ball is launched upward from a height 40 feet above ground level. The ball’s height at t seconds is given by -16t^2=128=40 .
Nesterboy [21]

Answer:

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

Step-by-step explanation:

<u><em>The correct question is</em></u>

A ball is launched upward from a height 40 feet above ground level. the ball's height at t seconds is given by h(t)=-16t^2+128t+40 At what time(s) will the ball be at 100 feet?

we have

h(t)=-16t^{2}+128t+40

so

For h(t)=100 ft

substitute in the equation and solve for x

-16t^{2}+128t+40=100

-16t^{2}+128t-60=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-16t^{2}+128t-60=0

so

a=-16\\b=128\\c=-60

substitute in the formula

x=\frac{-128(+/-)\sqrt{128^{2}-4(-16)(-60)}} {2(-16)}

x=\frac{-128(+/-)\sqrt{12,544}} {-32}

x=\frac{-128(+/-)112} {-32}

x=\frac{-128(+)112} {-32}=0.5

x=\frac{-128(-)112} {-32}=7.5

therefore

The ball will be at 100 feet at time x=0.5 sec and at time x=7.5 sec

7 0
4 years ago
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