Answer:
The probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
Step-by-step explanation:
Represent the provided data as follows:
Compute the probability of the number of Protestants that were calm for 2 out of 3 days as follows:
The number of Protestants surveyed is, <em>n</em> (Protestants) = 99.
The number of Protestants who were calm for 2 days,
<em>n</em> (Protestants who were calm for 2 days) = 6
The required probability is:
Thus, the probability of the number of Protestants that were calm for 2 out of 3 days is 0.061.
Stan's heart rate, in beats per minute, was measured 20 times at random. The results are 82, 84, 98, 112, 97, 93, 91, 87, 112, 8
Licemer1 [7]
Answer:
(80.4942, 94.9052)
Step-by-step explanation:
The sample mean is x = 87.7.
The sample standard deviation is s = 11.26.
At 99% confidence and 19 degrees of freedom, the critical value is t = 2.861.
The confidence interval is:
x ± t (s/√n)
87.7 ± 2.861 (11.26 / √20)
87.7 ± 7.2053
(80.4947, 94.9053)
20 ounces converts to 1.25 pounds.
(Hope this helps you! Feel free to message me if you have any additional questions. :) Have a nice day!)
Answer:
12. Option b: 20 is the correct answer.
13. Option a: A rose costs $1 more than a daisy is the correct answer.
Step-by-step explanation:
12. Given that:
15x+10y=700 Eqn 1
x+y=60 Eqn 2
To find x, we will eliminate y be multiplying Eqn 2 by 10
10(x+y=60)
10x+10y=600 Eqn 3
Subtracting Eqn 3 from Eqn 2
(15x+10y)-(10x+10y)=700-600
15x+10y-10x-10y=100
5x=100
Dividing both sides by 5
Hence,
Option b: 20 is the correct answer.
13. Given that:
5x+4y=32 Eqn 1
x+6y=22 Eqn 2
Multiplying Eqn 2 by 5
5(x+6y=22)
5x+30y=110 Eqn 3
Subtracting Eqn 1 from Eqn 3
(5x+30y)-(5x+4y)=110-32
5x+30y-5x+4y=78
26y=78
Dividing both sides by 26
Putting y=3 in Eqn 2
x+6(3)=22
x+18=22
x=22-18
x=4
Hence,
Option a: A rose costs $1 more than a daisy is the correct answer.
270.1666666666667 this is the anwser
