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storchak [24]
3 years ago
13

PLEASE I ONLY HAVE 30 MIUNUTES TO FINISH!!!!!!!!!!!!!

Mathematics
2 answers:
rjkz [21]3 years ago
8 0

Answer:

A and C

when the population is small and when the sample contains proportions of items/events/people that are different from those of the population

Step-by-step explanation:

creativ13 [48]3 years ago
3 0

Answer:

When it is small & when the sample has things that are different from the population.

Step-by-step explanation:

A small sample has less chance of accurately reflecting a population & too many variables can also negatively influence the study.

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What do you call -6 and 6
Oduvanchick [21]
The first one is negative six and the second one is positive six
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3 years ago
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Find the amount of 30000 naira 5 and half years at 7%​
Nataly_w [17]

Answer:41550

Step-by-step explanation:

30000×.07=2100

2100×5.5=11550

11550+30000=41550

5 0
3 years ago
binks need to raise at least $3600. He was given $200 and plans to save $50 per week. Select all the inequalities in this situat
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Answer:

First of read all formulas

Step-by-step explanation:

Calculate 50 *7 and add 350 and 200

6 0
3 years ago
32=x+17 help me pls if can because I don't know
Natalka [10]
Subtract 17from both sides
32-17=x
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6 0
3 years ago
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An independent-measures research study was used to compare two treatment conditions with n= 12 participants in each treatment. T
Maurinko [17]

Answer:

(a) The data indicate a significant difference between the two treatments.

(b) The data do not indicate a significant difference between the two treatments.

(c) The data indicate a significant difference between the two treatments.

Step-by-step explanation:

Null hypothesis: There is no difference between the two treatments.

Alternate hypothesis: There is a significant difference between the two treatments.

Data given:

M1 = 55

M2 = 52

s1^2 = 8

s2^2 = 4

n1 = 12

n2 = 12

Pooled variance = [(n1-1)s1^2 + (n2-1)s2^2] ÷ (n1+n2-2) = [(12-1)8 + (12-1)4] ÷ (12+12-2) = 132 ÷ 22 = 6

Test statistic (t) = (M1 - M2) ÷ sqrt [pooled variance (1/n1 + 1/n2)] = (55 - 52) ÷ sqrt[6(1/6 + 1/6)] = 3 ÷ 1.414 = 2.122

Degree of freedom = n1+n2-2 = 12+12-2 = 22

(a) For a two-tailed test with a 0.05 (5%) significance level and 23 degrees of freedom, the critical values are -2.069 and 2.069.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 falls outside the region bounded by the critical values.

(b) For a two-tailed test with a 0.01 (1%) significance level and 23 degrees of freedom, the critical values are -2.807 and 2.807.

Conclusion:

Fail to reject the null hypothesis because the test statistic 2.122 falls within the region bounded by the critical values.

(c) For a one-tailed test with 0.05 (5%) significance level and 23 degrees of freedom, the critical value is 1.714.

Conclusion:

Reject the null hypothesis because the test statistic 2.122 is greater than the critical value 1.714.

6 0
3 years ago
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