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3 years ago

16. Subtract: 5 - 3 1/3

Mathematics

2 answers:

devlian [24]3 years ago

4 0

Turn in an improper fraction
3 1/3
= 10/3

5/1 - 10/3

15/3 - 10/3

5/3 or 1 2/3

Varvara68 [4.7K]3 years ago

3 0

Answer:

1 2/3 ( d is the answer)

Step-by-step explanation:

See image below:) I know it says 5/3 but where it says alternative form it says 1 2/3

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Math! 30 points + brainliest

Ronch [10]

Answer:

A) 9.56x10^38 ergs

B) 7.4x10^-3 mm

Step-by-step explanation:

A) 9.56x10^38 ergs B) 7.4x10^-3 mm A). For the sun, just multiply the power by time, so 3.9x10^33 erg/sec * 2.45x10^5 sec = 9.56x10^38 B) Of the two values 7.4x10^-3 and 7.4x10^3, the value 7.4x10^-3 is far more reasonable as a measurement for blood cell. Reason becomes quite evident if you take the 7.4x10^3 value and convert to a non-scientific notation value. Since the exponent is positive, shift the decimal point to the right. So 7.4x10^3 mm = 7400 mm, or in easier to understand terms, over 7 meters. That is way too large for a blood cell when you consider that you need a microscope to see one. Now the 7.4x10^-3 mm value converts to 0.0074 mm which is quite small and would a reasonable size for a blood cell.

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3 years ago

Read 2 more answers

What is the correct equation to solve for X?

Vanyuwa [196]

It’s the second option
sin(45)=13/x

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2 years ago

HELP ME ASAP! Will give BRAINLIEST! Please read the question THEN answer correctly! No guessing. Check all that apply.

Vesnalui [34]

It’s the third one - I tried :)

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3 years ago

I need help with this <br> ASAP!!

liraira [26]

Answer:=

−243 /512 Fraction

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3 years ago

Please Help Me! I will give all my point to who ever answers my question!!!

love history [14]

Step-by-step explanation:

The equation that is given is only for the specific place of that object. To find the velocity, you need to take the derivative of the equation. This will give you:

$V=2+\frac{1}{2} t$

Now, to find the average velocity of this object, plug in the values given to you. It's between the time interval [1, 2] so these are the two numbers you'll plug into the velocity equation. Finding this average is like finding any other average.

$V(1)=2+\frac{1}{2} (1)\\V(1)=2+\frac{1}{2}=\frac{5}{2}\\V(2)=2+\frac{1}{2}(2)\\V(2)=2+1=3$

$V_{avg}=\frac{3-\frac{5}{2} }{2-1} \\V_{avg}=\frac{\frac{6}{2}-\frac{5}{2} }{1} \\V_{avg}=\frac{1}{2}$

Average velocity is 0.5 sec

To find instantaneous velocity just find the velocity at time one. Think about the name "instantaneous velocity," it's the velocity in that <u>instant</u>.

We already found this, so I don't need more work (it's displayed above).

The instantaneous velocity when $t=1$ is 2.5 sec.

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3 years ago