24 half-kg packets = 24 x 1/2 = 12kg
Sugar remained = 50 - 12 = 38 kg
Answer: 38 kg
B= 2000 + CD
98000 = B + CD
substitute b in
98000 = 2000 + CD + CD
add variables
98000 = 2000 + 2CD
subtract 2000 from each side
96000 = 2CD
divide each side by 2
48000 = CD
Answer:
a) F
b) B, E, D
Step-by-step explanation:
a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values
From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2
The gradient of F = (-3units)/(1 unit) = -3
The gradient of A = 4/4 = 1
The gradient of C = -2/5
The gradient of D = 2/6 = 1/3
The gradient of E = 3/4
The segment with the greatest gradient is F
b) The steepest segment has the higher gradient
From their calculated we have;
The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3
Therefore, we have;
B, E, D.
Answer:
I belive x=4.9
Step-by-step explanation:
