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Alexxandr [17]
3 years ago
7

Solve for each variable x & y.

Mathematics
2 answers:
Alex787 [66]3 years ago
5 0
X=4 and y=7 hope this helps
vodka [1.7K]3 years ago
4 0

Answer:

x=4 and y=7. did this help

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The largest state in the US is Alaska, covering 663,267 square miles (including water). What is the approximate radius of a sphe
JulsSmile [24]
Remember that the formula for the surface area of a sphere is SA=4 \pi r ^{2} . Substitute the given surface area to solve: 663,267=4 \pi r ^{2}. Divide by 4 on both sides: 165,816.75= \pi r ^{2}. Divide by pi on both sides: 52781.11= r ^{2}. Square root on both sides to find the radius: 229.741= r
5 0
3 years ago
Please help!!! I’ll mark you as brainliest!!!
Sedaia [141]
Ok I’ll break this down so it’s easier to understand:

So you start of with $80

The first step is to find 20% off

An easy way to find 20% is to divide it by 5.

80/5= 16

And since it’s 20% OFF we subtract 16 from 80

80-16= 64

Next we need to do the coupon

It is $5 off so

64-5= 59

And finally the rebate which is $2

59-2= 57

Answer:
57
3 0
3 years ago
Read 2 more answers
Select the correct word to describe the function. the equation y = startfraction 5 x cubed over 8 endfraction represents functio
balandron [24]

The functions and their descriptions are:

  • Polynomial: y = \frac{5x^3}{8} and y = 5x^3 + 8
  • Logarithm: y = 6 + 0.25\ln(x)
  • Exponential y = \frac{18}{1 + 6e^{-0.25x}}

<h3>How to describe the functions?</h3>

The functions are given as:

y = \frac{5x^3}{8}

y = 6 + 0.25\ln(x)

y = \frac{18}{1 + 6e^{-0.25x}}

y = 5x^3 + 8

The functions would be described based on the type of function they represent.

Functions that use the "ln" keyword are logarithmic functions, while functions that use the "e" keyword are exponential functions.

Read more about functions at:

brainly.com/question/4025726

#SPJ1

7 0
2 years ago
Michael has some coins in his pocket consisting of dimes, nickels, and pennies. He has two more nickels than dimes, and three ti
velikii [3]
X = number of dimes 
x + 2 = number of nickels
3(x + 2) = number of pennies 

10x + 5(x + 2) + 3(x + 2) = 52
10x + 5x + 10 + 3x + 6 = 52
18x = 36
x = 2

x = 2 (number of dimes)
x + 2 = 4 (number of nickels)
3(x + 2) = 12 (number of pennies)

Check:
2(10) = 20 cents in dimes
4(5) = 20 cents in nickels
12(1) = 12 cents in pennies
Total = 52 cents 
7 0
4 years ago
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A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others
Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

  • If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

  • If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0
3 years ago
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