Z = (x - m)/s
z = (38-40)/8
z = -2/8
z = -1/4
z = -0.25
The z score is -0.25
Answer:
they are adjacent angles
Step-by-step explanation:
Answer:
Integers are a series of positive and negative numbers. When adding such numbers students have to pay attention to the sign that precedes the numbers in the equation. Generally, adding a value to a negative value is like subtracting the negative value from the positive one.
Step-by-step explanation:
Answer:

Step-by-step explanation:
Suppose at t = 0 the person is 1m above the ground and going up
Knowing that the wheel completes 1 revolution every 20s and 1 revolution = 2π rad in angle, we can calculate the angular speed
2π / 20 = 0.1π rad/s
The height above ground would be the sum of the vertical distance from the ground to the bottom of the wheel and the vertical distance from the bottom of the wheel to the person, which is the wheel radius subtracted by the vertical distance of the person to the center of the wheel.
(1)
where
is vertical distance from the ground to the bottom of the wheel,
is the vertical distance from the bottom of the wheel to the person, R = 10 is the wheel radius,
is the vertical distance of the person to the center of the wheel.
So solve for
in term of t, we just need to find the cosine of angle θ it has swept after time t and multiply it with R

Note that
is negative when angle θ gets between π/2 (90 degrees) and 3π/2 (270 degrees) but that is expected since it would mean adding the vertical distance to the wheel radius.
Therefore, if we plug this into equation (1) then
