There can be 6 teams because
27/4= 6.75
yet there will be 3 students left, so they can be a team ;)
Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Answer:
Refer to your notes from module 6 on this.
Step-by-step explanation:
Complete this test question just like you did the practice question from the module. Remember your test is an open note test, but it is not a copy from the internet test. You can do it!!!
Use the property that angles sum up to 360 degrees.
Also use property that <M = <R and <A = <P.
That gives the following equation:
m<R + m<A + m<M + m<P = 360
6x+5 + 9x+25 + 6x+5 + 9x+25 = 360
30x + 60 = 360
x = 10
Answer:
x = 10
m<M = 6x+5 = 65 degrees
