Answer:
Let P be the external point. O be the origin. join O and P get OP and nearest point on the circle from P be A.
Let Q be the point onthe circle in which, tangent make 90° with radius at Q.
PQ = 8 and OQ = 6
we get a right angled triangle PQO right angled at Q.
so, OP^2 = OQ^2 + PQ^2= 8^2 + 6^2 = 64 + 36 =1==
therefore OP =10cm
we need nearest point from P, which is PA
PA = OP - OA= 10 -6=4cm
Answer:

Step-by-step explanation:
6 + 12 + 24 + 48 + 96 =
= 6 + 6 * 2 + 6 * 4 + 6 * 8 + 6 * 16
= 6 + 6 * 2^2 + 6 * 2^2 + 6 * 2^3 + 6 * 2 * 4
= 6 * 2^(n - 1)

Answer:
-2/1
Step-by-step explanation:
i hope this helps :)
Answer:
18
Step-by-step explanation:
Soz man i use the metric system