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3 years ago

Divide using long division. (x3 + 3x2 + x - 4) + (x - 1)

Mathematics

2 answers:

Shalnov [3]3 years ago

5 0

Answer:

2x+3x2 +x3 −5

Step-by-step explanation:

Hope this helps

Lilit [14]3 years ago

3 0

Answer:

x^2 - 2x + 2

step-step explanation:

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Help please I don’t get it

AlexFokin [52]

Answer:

3/8

Step-by-step explanation:

Rearrange, find common denominator.

$x = \frac{7}{8} - \frac{1}{2} \\ x = \frac{7}{8} - \frac{4}{8} \\ x = \frac{3}{8}$

8 0

2 years ago

Read 2 more answers

1. Identify your variables using let statements.

Advocard [28]

The number of chicken dish is 131 dishes while the number of lobster dishes is 119 dishes

<h3>How to find the number of each type of dish.</h3>

Let

x = number of chicken dish and
y = number of lobster dish

<h3>How to determine the equations for the linear system</h3>

Since it cost $40 per dish for chicken dish, the total cost of chicken dish is 40x.

Also, since it cost $70 per dish for lobster dish, the total cost of lobster dish is 70y

So, the total cost of dish is T = 40x + 70y

Also, we know that the total cost of dish is $13,570.

So, 40x + 70y = 13570 (1)

Also, there are going to be 250 guest at the dinner and thus 250 dishes.

So, the total number of dishes is x + y = 250

So, x + y = 250 (2)

So, the equations of the linear system are

40x + 70y = 13570 (1)

x + y = 250 (2)

<h3>How to determine the solution for the linear system</h3>

Since

40x + 70y = 13570 (1)

x + y = 250 (2)

From (2), x = 250 - y

Substituting x into (1), we have

40x + 70y = 13570 (1)

40(250 - y) + 70y = 13570 (1)

10000 - 40y + 70y = 13570

30y = 13570 - 10000

30y = 3570

y = 3570/30

y = 119

Substituting y = 119 into x, we have

x = 250 - y

x = 250 - 119

x = 131

Therefore, the number of chicken dish is 131 dishes while the number of lobster dishes is 119 dishes

Learn more about equation of linear system here:

brainly.com/question/13729904

#SPJ1

7 0

2 years ago

The Gomez family just purchased a $2,574.54 laptop computer. They made a down payment of $574.54. Through the store's installmen

Maurinko [17]

A) The amount financed is the purchase amount less the down payment.
$2,574.54 -574.54 = $2000.00

B) The finance charge is the total of payments less the amount financed.
18*$121.00 -2000.00 = $178.00

C) The APR is calculated by a financial calculator to be 10.96%.

3 0

2 years ago

Place the circles in order from the circle with the largest area to the circle with the smallest area.

11111nata11111 [884]

Answer:

Diameter 16, radius 7, circumference 37.68, diameter 8

Step-by-step explanation:

Largest area will be in a circle with the largest radius. So let's find all radii.

d = 8, so r = 4;

r = 7;

circumference = 2pi*r = 37. 68, so r = 6

diameter 18, so r = 8

5 0

3 years ago

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

8 0

3 years ago