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FromTheMoon [43]
3 years ago
5

Given that

ormula1" title="\frac{8-3\sqrt{2} }{2} = a+b\sqrt{2}" alt="\frac{8-3\sqrt{2} }{2} = a+b\sqrt{2}" align="absmiddle" class="latex-formula">
Find a and b
Mathematics
1 answer:
bearhunter [10]3 years ago
6 0

Answer:

a = 4, b = - \frac{3}{2}

Step-by-step explanation:

Given

\frac{8-3\sqrt{2} }{2} = a + b\sqrt{2} ( multiply both sides by 2 to clear the fraction )

8 - 3\sqrt{2} = 2a + 2b\sqrt{2}

For the 2 sides to be equal , then

2a = 8 ( divide both sides by 2 )

a = 4

and

2b = - 3 ( divide both sides by - 2 )

b = - \frac{3}{2}

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