9514 1404 393
Answer:
2 3/4 years
Step-by-step explanation:
The interest is given by the formula ...
I = Prt . . . . . . principal P at annual rate r for t years
Solving for t gives ...
t = I/(Pr)
t = 4167.90/(16840×0.09) = 2.75
The duration of the loan is 2 3/4 years.
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
The answer is that his average is 75.5 for the second nine weeks
Answer:
a) Domain: x≥0
b) Range: y≤-2
c) x-intercepts: None
d) y-intercepts: (0,-2)
e) f(4)= -4
Step-by-step explanation:
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