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masya89 [10]
3 years ago
6

use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11

)

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}

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triangle AMY ~ MEG , AM = 5 MY=7 AY =3. MEG IS A DILATION of AMY by a scale facyor of 1/3. fimd the perimeter of MEG.
Mademuasel [1]

Answer:

7

Explanation:

From the question, we're told that triangles AMY and MEG are similar. If triangle AMY has sides AM = 5, MY = 7, and AY = 3 then we can find the side lengths of triangle MEG since we're told from the question that it is a dilation of AMY by a scale factor of 1/3.

So all we need to is multiply the corresponding sides of AMY by 1/3, so we'll have;

\begin{gathered} ME=5\ast\frac{1}{3}=\frac{5}{3} \\ EG=7\ast\frac{1}{3}=\frac{7}{3} \\ MG=3\ast\frac{1}{3}=3 \end{gathered}

We can then go ahead and find the perimeter of MEG. Note that to find the perimeter of a triangle, we add all the length of its sides;

\begin{gathered} \text{Perimeter of MEG}=\frac{5}{3}+\frac{7}{3}+3 \\ =\frac{5+7+9}{3} \\ =\frac{21}{3} \\ =7 \end{gathered}

The perimeter of MEG is 7.

6 0
1 year ago
Omar is putting 5 liters of water in two goldfish bowls. He spills 200 milliliters of water and divides the remaining water even
DedPeter [7]

Answer:

a) 0.2 L

b) 4800 ml

c) 2400 ml

Step-by-step explanation:

Total volume of water = 5 litres

Since 1000 milliliters make 1 L

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a) litres of water spilt = 200/1000 = 0.2 L

b) milliliters of water remaining = 5000 - 200 = 4800 ml

c) since it was expressly stated in the question that the remaining water was divided evenly; 4800/2 = 2400 ml in each bowl

4 0
3 years ago
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