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3 years ago

A cylinder has a radius of 3.2 meters its volume is 190 Cubic meters find its height to the nearest 10th of a meter

Mathematics

1 answer:

Stels [109]3 years ago

5 0

Answer:

volume = pi r^2 h

or, 190 = pi (3.2)^2 h

or, 190/10.24 = pi h

or, 18.56 = 22/7 h

or, 18.56×7/22 = h

thus , h = 5.9037

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What is the perpendicular line slope of -2x-9y=4

zimovet [89]

The slope would be 9/2

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3 years ago

A tree casts shadow 26 ft long. A 3 ft tall flowers casts a shadow 4 ft long. How tall is the tree?

Rufina [12.5K]

Answer:

19. 5 feets

Step-by-step explanation:

Shadow of tree = 26 feets

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Shadow of flower = 4 feets

Height of sun Innthe sky:

Shadow of flower / height of flower

= 4/3 = 1.333333

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Question in photo!! Will mark Brainlyist

victus00 [196]

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Option B.

$a$

Step-by-step explanation:

Given:

-3( -x + a ) + 7 < 5 When x = -1

To Find:

a ?

Solution:

-3( -x + a ) + 7 < 5 When x = -1

Substitute x = -1 in above we get

-3(-(-1) + a ) + 7 < 5

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$\therefore -3\times 1 +(-3)\times a$

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3 years ago

Help for brainliest and 10 points

Travka [436]

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2 years ago

If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

3 0

3 years ago