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N76 [4]
3 years ago
9

A cylinder has a radius of 3.2 meters its volume is 190 Cubic meters find its height to the nearest 10th of a meter

Mathematics
1 answer:
Stels [109]3 years ago
5 0

Answer:

volume = pi r^2 h

or, 190 = pi (3.2)^2 h

or, 190/10.24 = pi h

or, 18.56 = 22/7 h

or, 18.56×7/22 = h

thus , h = 5.9037

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y=x^2 + 3x - 3

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The cooking time for a piece of meat is proportional to the weight of the meat. What is the value of the constant for this relat
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3 years ago
The accompanying data contains the depth​ (in kilometers) and​ magnitude, measured using the Richter​ Scale, of all earthquakes
Sunny_sXe [5.5K]

Answer:

Depth:

μ =20.2025 km

M = 15.625 km

Range = 47.15 km

σ ≈ 15.92 km

Q₁ = 5.7375 km

Q₃ =  34.6675 km

Magnitude:

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

Step-by-step explanation:

The given data are;

Depth {}                                 Magnitude

0.76 {}                                    0.84

4.93 {}                                    0.47

8.16 {}                                     0.35

33.58 {}                                  1.32

21.2 {}                                     1.61

35.03 {}                                  4.57

10.05 {}                                   5.52

47.91 {}                                    1.99

For the Depth, we have;

The mean, μ = (0.76+4.93+8.16+33.58+21.2+35.03+10.05+47.91)/8 =20.2025 km

The median, M = The (n + 1)/2th term after arranging the term in increasing order as follows;

0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 , the median is therefore;

(8 + 1)/2th term or the 4.5th term which is 10.05 + (21.2 - 10.05)/2 = 15.625 km

The Range = The highest - The lowest value = 47.91 - 0.76 = 47.15 km

The Standard deviation of, σ, is given as follows;

\sigma =\sqrt{\dfrac{\sum \left (x_i-\mu  \right )^{2} }{N}}

Where;

x_i = The individual data point = (0.76, 4.93, 8.16, 10.05, 21.2, 33.58, 35.03, 47.91 )

N = The total number of data point = 8

Substituting, (using Microsoft Excel) we get;

\sigma =\sqrt{\dfrac{\sum \left (x_i-20.2025  \right )^{2} }{8}} \approx 15.92 \ km

Q₁ = The first quartile = The (n + 1)/4th =  term arranged in increasing order

Q₁ = The (8 + 1)/4th term = The 2.25th term = 4.93 + (8.16 - 4.93)×0.25) = 5.7375 km

Q₃ = The first quartile = The 3×(n + 1)/4th =  term arranged in increasing order

Q₃ = The 3×(8 + 1)/4th term = The 6.75th term = 33.58 + 3×(35.03 - 33.58)×0.25) = 34.6675 km

For the magnitude, we have, using the same formulas and procedures as above;

μ = 2.08375

M = 1.465

Range, R = 5.17

σ = 1.801485 ≈ 1.8

Q₁ = 0.5625

Q₃ = 3.925

4 0
3 years ago
Solve 7x - 2z = 4- xy for x.
ExtremeBDS [4]

Answer:

0

Step-by-step explanation:

7x + -2z = 4 + -1xy

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add 'xy' to each side of the equation.

7x + xy + -2z = 4 + -1xy + xy

Combine like terms: -1xy + xy = 0

7x + xy + -2z = 4 + 0

7x + xy + -2z = 4

Add '2z' to each side of the equation.

7x + xy + -2z + 2z = 4 + 2z

Combine like terms: -2z + 2z = 0

7x + xy + 0 = 4 + 2z

7x + xy = 4 + 2z

Reorder the terms:

-4 + 7x + xy + -2z = 4 + 2z + -4 + -2z

Reorder the terms:

-4 + 7x + xy + -2z = 4 + -4 + 2z + -2z

Combine like terms: 4 + -4 = 0

-4 + 7x + xy + -2z = 0 + 2z + -2z

-4 + 7x + xy + -2z = 2z + -2z

Combine like terms: 2z + -2z = 0

-4 + 7x + xy + -2z = 0

8 0
3 years ago
Write an expression that represents the area of a circle with radius 3x^3. (For any circle with radius r, a=π r^2 = π .r .r ^.)
aalyn [17]

9514 1404 393

Answer:

  B. 9πx^6

Step-by-step explanation:

Putting the given radius into the area formula gives ...

  A = πr^2

  A = π(3x^3)^2 = π(3^2)(x^(3·2))

  A = 9πx^6

6 0
3 years ago
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