Here, you have to combine like terms. So, it is 11m-3v.
Answer:
28 students
Step-by-step explanation:
Let number of students in cooking club = x
Number of students in fencing club = 1/5 x
Number of students in chess club = 2(1/5)x
Since, There are 42 more students in the cooking club than in the chess club
Then ;
Number of students in chess club = Number of students in cooking club - 42
2(1/5)x = x - 42
(2/5)x - x = - 42
(2/5)x - x = - 42
-0.6x = - 42
x = 42 / 0.6
x = 70
Hence, number of students in chess club :
(2/5) * 70 = 28
P + s = 200......p = 200 - s
20p + 15s = 3400
20(200 - s) + 15s = 3400
4000 - 20s + 15s = 3400
-20s + 15s = 3400 - 4000
-5s = - 600
s = -600/-5
s = 120 <=== there were 120 standard tickets sold
p + s = 200
p + 120 = 200
p = 200 - 120
p = 80 <=== there were 80 premium tickets sold
Answer:
The solution region is x < –5 and x > 2
Step-by-step explanation:
We are given the inequalities, 2x–2 < –12 or 2x+3 > 7
Upon simplifying the inequalities, we get,
A. 
i.e. 
i.e. 
B. 
i.e. 
i.e. 
So, we get the solution is 
or 
and the plotted region can be seen below.
