All categories

2 years ago

Lowest common multiple of 3240 and 1007

Mathematics

1 answer:

xeze [42]2 years ago

4 0

Answer:

3,262,680

Step-by-step explanation:

Hope this helps!

You might be interested in

Perimeter of a triangle is 27cm,if two sides measure 9cm and 7.8cm,find the measure of third side?

fredd [130]

Answer:

10.2cm

Step-by-step explanation:

Perimeter is the sum of the lengths of all sides.

1st side: 9cm

2nd side: 7.8cm

Perimeter: 27cm

Perimeter = 1st + 2nd +3rd side of a triangle

27cm = 9cm +7.8cm + 3rd side

3rd side = 27cm - 9cm -7.8cm

= 10.2cm

8 0

2 years ago

A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$

c) What is the probability that two or more are essay?

$P(X\geq2)=1-(P(0)+P(1))=1-(0.3174+0.4232)=1-0.7406=0.2594$

8 0

3 years ago

True or false:x/3 is equivalent to 1/3x.explain your reasoning.

KIM [24]

That is true because you are still dividing x by three either way

8 0

3 years ago

Read 2 more answers

Solve 2x2 + 8x + 10 = 0. using this model to he<br> X =<br> -b+ ✓ 62 - 4ac<br> 2a

Lesechka [4]

Answer:

x can have two complex solutions, which are:

-2 + i

-2 - i

Step-by-step explanation:

2x² + 8x + 10 = 0

4x² + 16x + 20 = 0

4x² + 16x + 16 = -4

(2x + 4)² = -4

2x + 4 = √-4

2x = -4 ± i√4

2x = -4 ± 2i

x = -2 ± i

So x is equal to -2 + i and -2 - i.

8 0

3 years ago

Talia used 1/3 of a piece of wood for the base of her project 1/4 of the piece of wood for the vertical support and the rest for

Veseljchak [2.6K]

Answer:

The fraction of wood used for horizontal support is $\frac{5}{12}$ .

Step-by-step explanation:

Assume that the total piece of wood is of length 1.

It is provided that Talia used $\frac{1}{3}$ of the piece of wood for the base of he project.

She use $\frac{1}{4}$ of the piece of wood for the for the vertical support.

The remaining wood she used for horizontal support.

The amount of wood used for horizontal support can be computed by the subtracting the amount of wood used for base of the project and vertical support form 1.

Compute the amount of wood used for horizontal support as follows:

$Horizontal\ support=1-Base\ of\ project-Vertical\ support\\= 1 - \frac{1}{3}-\frac{1}{4}\\ =\frac{12-4-3}{12} \\=\frac{5}{12}$

Thus, the fraction of wood used for horizontal support is $\frac{5}{12}$ .

3 0

3 years ago