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3 years ago

Which statement best describes what occurs when a warm front occurs?

1 answer:

7 0

Answer: A

Explanation: Warm fronts cause snow flurries in the winter, while cold fronts cause several days of rainy weather so (C) wouldn’t be it. (D) is to Vague so it doesn’t best describe what occurs in a warm front. Last, (B) is wrong since the weather DOES change in a warm front. That leaves us with (A), so (A) is the correct Answer.

(Hope this helps! )

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Mama L [17]

<h3><u>Answer;</u></h3>

producing a path for current to flow

<h3><u>Explanation;</u></h3>

An AC generator is a device that converts mechanical energy into electrical energy using the principle of electromagnetic induction.
<em><u>Slip rings are two hollow rings to which two ends of the armature coil are connected. These rings rotate with the rotation of the coil. They function to to allow for electrical contact with the brushes.</u></em>
Slip rings therefore, provide a means for connecting the rotating armature to an external circuit.

3 0

4 years ago

Read 2 more answers

Which one of the following indicates a drop in temperature?

Nitella [24]

Answer: <span>D. A bimetallic strip bends so that the steel is on the outside curve
</span>
When something has an increased temperature, its volume will expand. Then, if the temperature drops, its volume should be smaller. From there option A and B are out since the liquid in thermometer is expand or move up.

When you put two kinds of different metal with a different coefficient of thermal expansion, the outer curve metal will be the one with lesser coefficient when temperature drop. Since the question about drop in temperature then the metal should be bend
Brass will expand 1.5 times more than the steel so the outer curve would be the steel.

6 0

4 years ago

A 56 kg diver runs and dives from the edge of a cliff into the water which is located 4.0 m below. If she is moving at 8.0 m/s t

Reil [10]

Answer:

1) 2197.44 J

2) 0 J

3) 2197.44 J = Constant

4) 2197.44 J

5) Approximately 8.86 m/s

Explanation:

The given parameters are;

The mass of the diver, m = 56 kg

The height of the cliff, h = 4.0 m

The speed with which the diver is moving, vₓ = 8.0 m/s

The gravitational potential energy = Mass, m × Height of the cliff, h × Acceleration due to gravity, g

1) Her gravitational potential energy = 56 × 4.0 × 9.81 = 2197.44 J

2) The kinetic energy = 1/2·m·u²

Where;

u = Her initial velocity = 0 when she just leaves the cliff

Therefore;

Her kinetic energy when she just leaves the cliff = 1/2 × 56 × 0² = 0 J

3) The total mechanical energy = Kinetic energy + Potential energy

The total mechanical energy is constant

Her total mechanical energy relative to the water surface when she leaves the cliff = Her gravitational potential energy = 2197.44 J = Constant

4) Her total mechanical energy relative to the water surface just before she enters the water = 2197.44 J

5) The speed with which she enters the water, v, is given from, v² = u² + 2·g·h

Where;

u = The initial velocity at the top of the cliff before she jumps= 0 m/s

∴ v² = 0² + 2 × 9.81 × 4 = 78.48

v = √78.48 ≈ 8.86 m/s

The speed with which she enters the water, v ≈ 8.86 m/s

7 0

3 years ago

Two students were pushing a heavy sofa. One student pushed with a force of 200.0 N to the right, while the other pushed with a f

makvit [3.9K]

Answer:

Explanation:

F = ma

a = F/m

a = (200.0 + 150.0 - 100.0) / 91.0

a = 250.0/91.0

a = 2.7472527...

a = 2.75 m/s²

8 0

2 years ago

3. A model rocket is launched straight upward at 58.8 m/s.

kolezko [41]

Answer:

a). 6 seconds

b). 12 seconds

c). 176.4 meters

Explanation:

a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,

v = u - gt

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational pull = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t = $\frac{58.8}{9.8}$

= 6 seconds

b). Total time of flight = 2(Time taken to go up)

= 2×6

= 12 sec

c). Formula to get the peak height is,

$h=ut-\frac{1}{2}gt^2$

h = (58.8)6 - $\frac{1}{2}(9.8)(6)^2$

= 352.8 - 176.4

= 176.4 meters

8 0

4 years ago