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blondinia [14]
3 years ago
15

A swimming pool is open for 7 1/2 hours during a day. The pool keeps one lifeguard on duty at a time and each life guards shift

is 1 1/2 hours long. How many shifts are there per day
Mathematics
1 answer:
xz_007 [3.2K]3 years ago
6 0

Answer:

5 shifts

Step-by-step explanation:

7 1/2= 7.5

1 1/2= 1.5

7.5/1.5= 5

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If blueberries cost $4.00 per pound, how many pounds of blueberries can you buy for $1.00?
Masteriza [31]

If x is the number of berries you can buy with 1 dollar,

1 pound of blueberries = $4.00

x pound of berries = $1.00

Lets set up a proportion- because these are directly proportional- when there is more pounds of berries, it will cost more.

\frac{1}{4.00} = \frac{x}{1.00}

Cross multiply

4x=1

Divide both sides by 4 to isolate x

x=1/4 or $0.25

7 0
3 years ago
Determine two angles between 0° and 360° that have a cosine of negative root3/2 without using a calculator
Naily [24]

Answer:

150° and 210°

Step-by-step explanation:

1) to drow a circle with radius=1 in the system of coordinates like in the attached picture;

2) to mark point (-√3/2)≈-0.866 on X-axis (in the picture it is the point M);

3) to graph line AB through point M, the line AB || Y-axis and the points A and B are on the circle with radius=1;

4) to measure the angles ∠ROA and ∠ROB (the points are marked with red colour);

5) finally, m(∠ROA)=150°; m(∠ROB)=210°.

5 0
3 years ago
Use the triangle shown to find m∠Q and m∠S.
Elodia [21]
<h2><u>Hope this helps :)</u></h2>

Step-by-step Example 1:

Two angles are supplementary. If the measure of the angle is twice the measure of the other, find the measure of each angle.

Let the measure of one of the supplementary angles be a .

Measure of the other angle is 2 times a .

So, measure of the other angle is 2a .

If the sum of the measures of two angles is 180° , then the angles are supplementary.

So, a+2a=180°

Simplify.

3a=180°

To isolate a , divide both sides of the equation by 3 .

3a3=180°3    a=60°

The measure of the second angle is,

2a=2×60°       =120°

So, the measures of the two supplementary angles are 60° and 120° .

Step-by-step Example 2:

Find m∠P  and  m∠Q if ∠P  and  ∠Q are supplementary, m∠P=2x+15 , and m∠Q=5x−38 .

The sum of the measures of two supplementary angles is 180° .

So, m∠P+m∠Q=180°

Substitute 2x+15 for m∠P and 5x−38 for m∠Q .

2x+15+5x−38=180°

Combine the like terms. We get:

7x−23=180°

Add 23 to both the sides. We get:

7x=203°

Divide both the sides by 7 .

7x7=203°7

Simplify.

x=29°

To find m∠P , substitute 29 for x in 2x+15 .

2(29)+15=58+15

Simplify.

58+15=73

So, m∠P=73° .

To find m∠Q , substitute 29 for x in 5x−38 .

5(29)−38=145−38

Simplify.

145−38=107

So, m∠Q=107° .

6 0
2 years ago
Find angle ADB of the equation
Aloiza [94]

Answer:

m\angle ADB = 59\°.

Step-by-step explanation:

Given:

\angle BDC = 31\°

We need to find \angle ADB.

Solution:

Now we can see that given figure is a rectangle with diagonals drawn in it.

So by properties of rectangle which states that;

"All angles of a rectangle are 90°."

So we can say that;

\angle A = \angle B = \angle C = \angle D = 90\°

But

\angle D = \angle BDC + \angle ADB

Substituting the values we get;

31\°+\angle ADB = 90\°

Subtracting both side by  by 31 we get;

31\°+\angle ADB -31\°= 90\°-31\°\\\\m\angle ADB = 59\°

Hence m\angle ADB = 59\°.

8 0
4 years ago
Divide. Give the quotient and remainder. ÷24,0336​
worty [1.4K]

Answer:

I believe it's three

Step-by-step explanation:

8 0
3 years ago
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