You move down 6 units and left 9 units. You end at (-5, -3). Where did you start?

Two trains left the cities A and B at the same time and headed towards each other. The cities are s miles apart. The first train

mezya [45]

The formula of t in terms of s , $v_{1}$ , $v_{2}$ is

$t=\frac{s}{(v_{1}+v_{2})}$

The value of t when s = 310 , $v_{1}$ = 75 , $v_{2}$ = 80 is 2 hours

Step-by-step explanation:

Two trains left the cities A and B at the same time and headed towards

each other

The cities are s miles apart
The first train was traveling at the speed of $v_{1}$ mph
The second train was traveling at the speed of $v_{1}$ mph
After t hours the two trains met each other

∵ The cities are s miles apart

∵ After t hours the two trains met each other

∴ s = $s_{1}$ + $s_{2}$ , where $s_{1}$ is the

distance that the 1st train moved in t hours and $s_{2}$

is the distance that the 2nd train moved in t hours

∵ s = v t

∴ $s_{1}$ = $v_{1}$ t

∴ $s_{2}$ = $v_{2}$ t

- Substitute them in the equation of s

∴ s = $v_{1}$ t + $v_{2}$ t

- Take t as a common factor in the right hand side

∴ s = t ( $v_{1}$ + $v_{2}$ )

- Divide both sides by ( $v_{1}$ + $v_{2}$ )

∴ $t=\frac{s}{(v_{1}+v_{2})}$

The formula of t in terms of s , $v_{1}$ , $v_{2}$ is

$t=\frac{s}{(v_{1}+v_{2})}$

∵ s = 310 m/h

∵ $v_{1}$ = 75 m/h

∵ $v_{2}$ = 80 m/h

- Substitute these values in the formula of t above

∴ $t=\frac{310}{(75+80)}=\frac{310}{155}$

∴ t = 2 hours

The value of t when s = 310 , $v_{1}$ = 75 , $v_{2}$ = 80 is 2 hours

Learn more:

You can learn more about distance, speed and time in brainly.com/question/1748290

#LearnwithBrainly

4 0

3 years ago

Order the following from least to greatest: |5|, -4, -|9|, -(-1), |-10|, -2.72

igor_vitrenko [27]

Answer:

-|9|, -4, -2.72, -(-1), |5|, |-10|

Step-by-step explanation:

numbers with | | around them have everything removed but the number.

7 0

2 years ago

1. En una comunidad del Cuzco la Lic. De Salud del Adulto Mayor (60 años a más) reportó los casos de diabetes de los seis primer

VARVARA [1.3K]

Answer:

The problem is about cases of diabetes in old people through months.

The variable is descrete , because it doesn't admit decimal numbers, it represents people, and people are whole numbers.

The frequency table would be

<h3> Months People</h3>

January 24

February 30

March 20

April 18

May 28

June 12

The total number of people is 132.

The mean would be the total number of people divided by the six months.

$\mu = \frac{132}{6} =22$

Therefore, the mean is 22 people per month.

Remember that the median is the value at the center of the data set, which is between March and April, so

$\frac{20+18}{2}=19$

Therefore, the mean is 19.

The third statistical value is determined by the major frequency. So, the data that repeats the most is February, which means that month encloses the majority of people.

8 0

3 years ago

Question answer safety and first aid

SCORPION-xisa [38]

It is a process of this activitie

5 0

3 years ago

Solve:7 +42-32-32 = 14.3-2a +7<br> A = -3<br> A= 0<br> A= 3<br> no solution

madreJ [45]

Answer:

a = 18.15

Step-by-step explanation:

$7+42-32-32=14.3-2a+7$

Combine like terms on the left side of the equation first. Add 7 and 42, then subtract 32 from the answer you get, then subtract 32 from that answer. This is going by order of PEMDAS.

Remember PEMDAS: (numbers 3 & 4 and numbers 5 & 6 are solved from left to right)