7 7/8= 63/8
3 1/4= 13/4
63/8 -13/4 we bring to the same denominator
(63-26)/8= 37/8
1) Determine the horizontal force, Fx, exerted by the block on Usain
cos(20°) = Fx / F => Fx = F*cos(20) = 1700N*cos(20) = 1597.48 N
2) Determine the Impulse of that force on Usain.
I = F*t = 1597.48N * 0.32s = 511.19 N*s
3) Determine change in momentum of Usain, Δp
Δp = I = 511.19 N*s
4) Find change if velocity
Δp = Δ(mV) = mΔV => ΔV = Δp / m = 511.19 N*s / 86 kg = 5.94 m/s
Given the Usain started from rest, the velocity is ΔV - 0 = 5.94 m/s
Answer: 5.94 m/s
To find surface area, we can use the equation:
SA=2lw+2wh+2lh, where:
l=10 in
w=3 in
h=7 in
SA=(2)(10)(3)+(2)(3)(7)+(2)(10)(7)
SA=60+42+140
SA=242 in²
Answer:
9 lb 3 oz
Step-by-step explanation:
(3 + 5) lb + (9 + 10) oz
8 lb + 19 oz
16 oz = 1 lb
(8 + 1) lb + (19 - 16) ox
9 lb 3 oz
Answer:
92.8 km
Step-by-step explanation:
s=d/t
58=d/1.6
58*1.6=d
92.8=d
