Answer:Set \displaystyle f\left(x\right)=0f(x)=0.
Step-by-step explanation:
Set \displaystyle f\left(x\right)=0f(x)=0.
If the polynomial function is not given in factored form:
Factor out any common monomial factors.
Factor any factorable binomials or trinomials.
Set each factor equal to zero and solve to find the \displaystyle x\text{-}x- intercepts.
Answer:
es la c
Step-by-step explanation:
Explicación paso a paso:ya que para que de 0 tiene que ser un número negativo, tiene que ser el número inverso a 2/3, entonces n= -2/3 que tiene el mismo valor absoluto que 2/3
If I did this right, it should be:
1. 130 degrees
2. 50 degrees
3. 130 degrees
4. 50 degrees
Here's hoping I'm right. lol
For this case we find the slopes of each of the lines:
The g line passes through the following points:

So, the slope is:

Line h passes through the following points:

So, the slope is:

By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.
It is observed that lines g and h are not parallel. We verify if they are perpendicular:

Thus, the lines are perpendicular.
Answer:
The lines are perpendicular.