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2 years ago

If you had 11 pieces of licorice to share equally among 5 people, how much licorice would each person get?

Mathematics

2 answers:

shutvik [7]2 years ago

8 0

Answer:

everyone would get 2 and there would be 1 leftover

Step-by-step explanation:

Tanya [424]2 years ago

6 0

2 for each and 1 left over

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Adecco Workplace Insights Survey sampled men and women workers and asked if they expected to get a raise or promotion this year

fgiga [73]

Answer:

(a) Null Hypothesis, $H_0$ : $p_1-p_2$ $\leq$ 0 or $p_1$ $\leq$ $p_2$

Alternate Hypothesis, $H_a$ : $p_1-p_2$ > 0 or $p_1$ > $p_2$

(b) $\hat p_1$ = sample proportion of men = $\frac{104}{200}$ = 0.52

$\hat p_2$ = sample proportion of women = $\frac{74}{200}$ = 0.37

(c) P-value is 0.0011.

Step-by-step explanation:

We are given that Adecco Workplace Insights Survey sampled men and women workers and asked if they expected to get a raise or promotion this year (USA Today, February 16, 2012).

Suppose the survey sampled 200 men and 200 women. If 104 of the men replied yes and 74 of the women replied yes.

Let $p_1$ = population proportion of men who replied yes

$p_2$ = population proportion of women who replied yes

(a) Null Hypothesis, $H_0$ : $p_1-p_2$ $\leq$ 0 or $p_1$ $\leq$ $p_2$ {means that the population proportion of men is less than or equal to the population proportion of women}

Alternate Hypothesis, $H_a$ : $p_1-p_2$ > 0 or $p_1$ > $p_2$ {means that the population proportion of men is more than the population proportion of women}

(b) $\hat p_1$ = sample proportion of men = $\frac{104}{200}$ = 0.52

$\hat p_2$ = sample proportion of women = $\frac{74}{200}$ = 0.37

The test statistics that will be used here is Two-sample z proportion statistics;

T.S. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of men who replied yes = 0.52

$\hat p_2$ = sample proportion of women who replied yes = 0.37

$n_1$ = sample of men = 200

$n_2$ = sample of women = 200

So, test statistics = $\frac{(0.52-0.37)-(0)}{\sqrt{\frac{0.52(1-0.52)}{200} +\frac{0.37(1-0.37)}{200} } }$

= 3.05

Now at 0.01 significance level, the z table gives critical value of 2.3263 for right-tailed test. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the population proportion of men is greater than the population proportion of women.

P-value is given by the following formula;

P(Z > 3.05) = 1 - P(Z $\leq$ 3.05)

= 1 - 0.99886 = 0.0011

Hence, the p-value is 0.0011.

8 0

3 years ago

Need your help, Answer ASAP PLZZ!!!

ss7ja [257]

Answer: m∠IJH = m∠JHL because they are Alternate Interior Angles

Step-by-step explanation:

6 0

2 years ago

4 + 6^2 + 9 ∙ 3 - 10

Korvikt [17]

4+6^2+9•3-10

PEMDAS
P=parentheses
E=exponent
m=multiplication
d=division
a=addition
s=subtraction

*no parentheses in this equation
*exponent = 6^2
6^2=36
4+36+9•3-10
*multiplication = 9•3
9•3=27
4+36+27-10
*addition=4+36+27
4+36+27=67
67-10
*subtraction=67-10
67=10=57

ANSWER=57

please give brainliest itd mean a lot<3

3 0

2 years ago

Is each pair of expressions equivalent? Select Yes or No. a. 8(−2 + −4) and −2(−8 − 12) b. −4(−2 + 3) and 2(4 − 6) c. −(−3)(−2 +

olga nikolaevna [1]

See photo for solution and mark me as brainliest if you think i helped!

3 0

3 years ago

Use the data in LAWSCH85 for this exercise. (i) Using the same model as in Problem 4 in Chapter 3, state and test the null hypot

natka813 [3]

Answer:

Step-by-step explanation:

In the model

Log (salary) = B0 + B1LSAT +B2GPA +B3log(libvol) +B4log(cost)+B5 rank+u

The hypothesis that rank has no effect on log (salary) is H0:B5 = 0. The estimated equation (now with standard errors) is

Log (salary) = 8.34 + .0047 LSAT + .248 GPA + .095 log(libvol)

(0.53) (.0040) (.090) (.033)

+ .038 log(cost) – .0033 rank

(.032) (.0003)

n = 136, R2 = .842.

The t statistic on rank is –11(i.e. 0.0033/0.0003), which is very significant. If rank decreases by 10 (which is a move up for a law school), median starting salary is predicted to increase by about 3.3%.

(ii) LSAT is not statistically significant (t statistic ≈1.18) but GPA is very significance (t statistic ≈2.76). The test for joint significance is moot given that GPA is so significant, but for completeness the F statistic is about 9.95 (with 2 and 130 df) and p-value ≈.0001.

6 0

3 years ago