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Flauer [41]
2 years ago
7

What is the equation of the line that passes through the points (4, 5) and (7, 3)

Mathematics
1 answer:
swat322 years ago
7 0

Answer:

y = -2/3x + 23/3

Step-by-step explanation:

Let equation of the line be y = mx + c

m = (3-5)/(7-4) = -2/3 gradient/slope formula

sub (4, 5)

5 = -2/3 (4) + c

c = 23/3

therefore, equation of the line is y = -2/3x + 23/3

Hope it helps! :)

This is a topic called coordinate geometry. If you would like to find out more you can follow learntionary on instagram. I'll be posting some notes on coordinate geometry soon and I'll also post other useful math stuff as well :)

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Need help with the blanks
Crazy boy [7]
Answers: 
33. Angle R is 68 degrees
35. The fraction 21/2 or the decimal 10.5
36. Triangle ACG
37. Segment AB
38. The values are x = 6; y = 2
40. The value of x is x = 29
41. C) 108 degrees
42. The value of x is x = 70
43. The segment WY is 24 units long
------------------------------------------------------
Work Shown:
Problem 33) 
RS = ST, means that the vertex angle is at angle S
Angle S = 44
Angle R = x, angle T = x are the base angles
R+S+T = 180
x+44+x = 180
2x+44 = 180
2x+44-44 = 180-44
2x = 136
2x/2 = 136/2
x = 68
So angle R is 68 degrees
-----------------
Problem 35) 
Angle A = angle H
Angle B = angle I
Angle C = angle J
A = 97
B = 4x+4
C = J = 37
A+B+C = 180
97+4x+4+37 = 180
4x+138 = 180
4x+138-138 = 180-138
4x = 42
4x/4 = 42/4
x = 21/2
x = 10.5
-----------------
Problem 36) 
GD is the median of triangle ACG. It stretches from the vertex G to point D. Point D is the midpoint of segment AC
-----------------
Problem 37)
Segment AB is an altitude of triangle ACG. It is perpendicular to line CG (extend out segment CG) and it goes through vertex A.
-----------------
Problem 38) 
triangle LMN = triangle PQR
LM = PQ
MN = QR
LN = PR
Since LM = PQ, we can say 2x+3 = 5x-15. Let's solve for x
2x+3 = 5x-15
2x-5x = -15-3
-3x = -18
x = -18/(-3)
x = 6
Similarly, MN = QR, so 9 = 3y+3
Solve for y
9 = 3y+3
3y+3 = 9
3y+3-3 = 9-3
3y = 6
3y/3 = 6/3
y = 2
-----------------
Problem 40) 
The remote interior angles (2x and 21) add up to the exterior angle (3x-8)
2x+21 = 3x-8
2x-3x = -8-21
-x = -29
x = 29
-----------------
Problem 41) 
For any quadrilateral, the four angles always add to 360 degrees
J+K+L+M = 360
3x+45+2x+45 = 360
5x+90 = 360
5x+90-90 = 360-90
5x = 270
5x/5 = 270/5
x = 54
Use this to find L
L = 2x
L = 2*54
L = 108
-----------------
Problem 42) 
The adjacent or consecutive angles are supplementary. They add to 180 degrees
K+N = 180
2x+40 = 180
2x+40-40 = 180-40
2x = 140
2x/2 = 140/2
x = 70
-----------------
Problem 43) 
All sides of the rhombus are congruent, so WX = WZ.
Triangle WPZ is a right triangle (right angle at point P).
Use the pythagorean theorem to find PW
a^2+b^2 = c^2
(PW)^2+(PZ)^2 = (WZ)^2
(PW)^2+256 = 400
(PW)^2+256-256 = 400-256
(PW)^2 = 144
PW = sqrt(144)
PW = 12
WY = 2*PW
WY = 2*12
WY = 24
3 0
3 years ago
I need to collect 30 stickers. Each bag of crisps contains 3 stickers. How many bags will I need to buy?
soldier1979 [14.2K]
Hey there :)

Let p represent the number of bags to be bought

We need to collect 30 stickers and each bag has 3 stickers

                    3p                                =                        30
                      ↑                                                           ↑
Number of stickers in a bad       Number of stickers to be collected

\frac{3p}{3} = \frac{30}{3}
p = 10

We need to buy 10 bags of crisps to have 30 stickers


5 0
3 years ago
Read 2 more answers
Which system has no solutions?
ale4655 [162]

Answer:

the answer is C. x<3 x<1 that is the answer

5 0
3 years ago
Which is the equation of a line that has a slope of -2/3 and passes through point (-3,-1)
DiKsa [7]

Answer:

y = -2/3x - 3

Step-by-step explanation:

y = mx + b

m = slope

(-3,-1) = (x,y)

<em>Plus in the coordinates</em>

-1 = -2/3(-3) + b

<em>negative times negative = positive</em>

-2/3 * -3 = 2

-1 = 2 +b

<em>Use inverse operations</em>

-2 --2

-3 = b

y = -2/3x - 3

5 0
3 years ago
Read 2 more answers
If f(x)=2x^3-x+c and f(2)=10 then what's the value of c?
Goshia [24]

Answer:

c = -4

Step-by-step explanation:

If f(x) = 2x^3 - x + c and f(2) = 10, plug in 2 for the x values in the function and make the function output 10.

10 = 2(2^3) - 2 + c    Now, we only have to deal with one variable, that is c.

10 = 2(8) - 2 + c

10 = 16 - 2 + c

10 = 14 + c

-4 = c    After simplifying, we get that c is -4.

To check this, plug in 2 for x, and -4 for c in the function. If the function produces 10 as the result, the halleluja!

f(2) = 2(2^3) - 2 - 4

f(2) = 2(8) - 2 - 4

f(2) = 16 - 2 - 4

f(2) = 10

7 0
2 years ago
Read 2 more answers
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