The area of a rectangle is A=LW, the area of a square is A=S^2.
W=S-2 and L=2S-3
And we are told that the areas of each figure are the same.
S^2=LW, using L and W found above we have:
S^2=(2S-3)(S-2) perform indicated multiplication on right side
S^2=2S^2-4S-3S+6 combine like terms on right side
S^2=2S^2-7S+6 subtract S^2 from both sides
S^2-7S+6=0 factor:
S^2-S-6S+6=0
S(S-1)-6(S-1)=0
(S-6)(S-1)=0, since W=S-2, and W>0, S>2 so:
S=6 is the only valid value for S. Now we can find the dimensions of the rectangle...
W=S-2 and L=2S-3 given that S=6 in
W=4 in and L=9 in
So the width of the rectangle is 4 inches and the length of the rectangle is 9 inches.
I think it would be around 7 lbs
(i could be wrong but i think this is about right)
9 3/4 = 39/4 mi/m
68 1/4 = 273/4 min
39/4 mutiply by 273/4 = 10647 / 16 mi = 665.4 mi
Answer:
-x = 14
is not equivalent to x + 10 = 2x - 4
hope it helps
Answer:
Surface Area of Triangular Prism=444 m
Surface Area of Square Pyramid= 146 cm
Step-by-step explanation:
Hope this helps.
