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Kay [80]
3 years ago
8

What is the difference between contact forces and forces that act through a force field?

Physics
1 answer:
STALIN [3.7K]3 years ago
8 0
Contact forces are forces that occur when two objects make contact, ex. Frictional Force. Non-contact forces occur without contact, ex. Gravitational Force or Electric Force.
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If two equal charges are separated by a certain distance, the force of repulsion is F. Given F1, if each charge in F1 is doubled
Alisiya [41]

Answer:F_2=16\times F_1

Explanation:

Given

Force of repulsion between two charge particle is given by force F

Electrostatic force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 is the charges  of particle

r=distance between charge particle

=\frac{kq^2}{r^2}when charges are doubled and distance is reduced to half

i.e. q become 2 q and r becomes 0.5 r

F_2=\frac{k(2q)^2}{(0.5r)^2}

F_2=\frac{kq^2}{r^2}\times 4\times 4

F_2=16\times F_1

         

6 0
4 years ago
A baseball is hit into the air with a velocity of 27 m/s. How high does it go?
Marizza181 [45]

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

8 0
3 years ago
What is indicated by the different colors in the my plate plan
astraxan [27]

the different kids of food and the amount you should eat of them.

green:veggies

red:fruits

orange:grains

purple:protein

blue:dairy

8 0
4 years ago
You are trying to overhear a juicy conversation, but from your distance of 24.0m , it sounds like only an average whisper of 40.
Neporo4naja [7]

Answer:

The distance is r_2  =  0.24 \  m

Explanation:

From the question we are told that

       The  distance from the conversation is r_1    =  24.0 \ m

       The  intensity of  the sound at your position is  \beta _1 =  40 dB

        The  intensity at the sound at the new position is  \beta_2 =  80.0dB

Generally the intensity in  decibel is  is mathematically represented as

      \beta  =  10dB log_{10}[\frac{d}{d_o} ]

The intensity is  also mathematically represented as

      d =  \frac{P}{A}

So

    \beta  =  10dB *  log_{10}[\frac{P}{A* d_o} ]

=>   \frac{\beta}{10}  =  log_{10} [\frac{P}{A (l_o)} ]

From the logarithm definition

=>    \frac{P}{A  *  d_o}  =  10^{\frac{\beta}{10} }

=>      P =  A (d_o ) [10^{\frac{\beta }{ 10} } ]

Here P is the power of the sound wave

 and  A is the cross-sectional area of the sound wave  which is generally in spherical form

Now the power of the sound wave at the first position is mathematically represented as

               P_1 =  A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]

Now the power of the sound wave at the second  position is mathematically represented as

               P_2 =  A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]

Generally  power of the wave is constant at both positions  so  

    A_1 (d_o ) [10^{\frac{\beta_1 }{ 10} } ]  = A_2 (d_o ) [10^{\frac{\beta_2 }{ 10} } ]

      4 \pi r_1 ^2   [10^{\frac{\beta_1 }{ 10} } ]  = 4 \pi r_2 ^2   [10^{\frac{\beta_2 }{ 10} } ]

        r_2 =  \sqrt{r_1 ^2 [\frac{10^{\frac{\beta_1}{10} }}{ 10^{\frac{\beta_2}{10} }} ]}

       substituting value

        r_2 =   \sqrt{ 24^2 [\frac{10^{\frac{ 40}{10} }}{10^{\frac{80}{10} }} ]}

        r_2  =  0.24 \  m

     

7 0
4 years ago
How do catalysts speed up reactions<br><br><br><br> please help quickly
MissTica
How do catalysts speed up reactions ?
 

by reducing the amount of energy required for the reaction to occur.  other factors such as <span>catalysts' ability to speed a process are temperature, concentration </span>
8 0
3 years ago
Read 2 more answers
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