Question

Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.063 V. How much work is done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside?

Answer 1

Answer:

$W=1.008\times 10^{-20}\ J$

Explanation:

Given that

Potential difference ,ΔV= 0.063 V

Charge q

$q=1.6\times 10^{-19}\ C$

The work done by electric force given as

W = ΔV . q

$W=0.063\times 1.6\times 10^{-19}\ J$

$W=1.008\times 10^{-20}\ J$