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borishaifa [10]
3 years ago
13

Suppose that the electric potential outside a living cell is higher than that inside the cell by 0.063 V. How much work is done

by the electric force when a sodium ion (charge = +e) moves from the outside to the inside?
Physics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer:

W=1.008\times 10^{-20}\ J

Explanation:

Given that

Potential difference ,ΔV= 0.063 V

Charge q

q=1.6\times 10^{-19}\ C

The work done by electric force given as

W = ΔV . q

W=0.063\times 1.6\times 10^{-19}\ J

W=1.008\times 10^{-20}\ J

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