Which value of x makes the equation 0.1x - 2.5 = 1.0 true A 10 B 15 C 20 D 35

Mathematics

2 answers:

julsineya [31]2 years ago

6 0

Answer:

D 35

Step-by-step explanation:

When figuring this out you can just plug in your answers if you want to take it the easier way by just putting in the 35 in places of x and multiplying 0.1 times 35 gets you 3.5 so 3.5 minus 2.5 is 1

boyakko [2]2 years ago

3 0

Answer:

xDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD

Step-by-step explanation:

DDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDDD.........................................................D :D

You might be interested in

Which ordered pair is the solution to the system of equations?

Tcecarenko [31]

The best way to answer this item is to use the Substitution method. Substitute the value of y from the first equation to the y of the second equation such that the second equation becomes,

-4x + 3(x - 4) = -3

Simplifying the equation,
-x = 9

Dividing both sides by -1 gives an answer of,
x = -9

Then, substitute the value of x in the first equation.
y = -9 - 4
 y = -13

The answer to this item is letter B.

6 0

2 years ago

Read 2 more answers

The length of a rectangle is 1 less than twice the width.

vladimir1956 [14]

$w-width\\2w-1-length\\w(2w-1)=2w^2-w-the\ area\\28\ ft^2-the\ area\\\\\text{The equation:}\\\\2w^2-w=28\qquad\text{subtract 28 from both sides}\\\\2w^2-w-28=0\\\\2w^2-8w+7w-28=0\\\\2w(w-4)+7(w-4)=0\\\\(w-4)(2w+7)=0\iff w-4=0\ \vee\ 2w+7=0\\\\w-4=0\qquad\text{add 4 to both sides}\\\boxed{w=4}\\\\2w+7=0\qquad\text{subtract 7 from both sides}\\2w=-7\qquad\text{divide both sides by 2}\\w=-3.5$