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3 years ago

Tessa shot 36 free throws. She made 27 of them. what fraction of her free throws did tessa make?

2 answers:

6 0

Tessa shot 36 free throws

She made 27

so 27/36 is how much she made

Now simplify 27/36

27/36 = 3/4 (after dividing 9 from top and bottom)

3/4 is your answer

hope this helps

Readme [11.4K]3 years ago

3 0

I think it’s like this

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What is the value of x in x + 129 = 237?

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Answer:

108

Step-by-step explanation:

237-129= 108

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2 years ago

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The government plans to build 75,000 new homes. 1/5 of the new homes will be built in a city near you. How many is that?

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The answer is 15,000 because 75000/5 = 15000.

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3 years ago

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2 years ago

Craig has a rectangle wooden deck that measures 799 inches by 245 inches that he wants to put a string of lights around. What le

tino4ka555 [31]

Answer:

He should buy lights that are 2088 inches long

Step-by-step explanation:

Craig has a rectangle wooden deck that measures 799 inches by 245 inches.

Let us say the length, L, is 799 inches and the breadth, B, is 245 inches.

He wants to put a string of lights around the deck.

This means that he needs to buy the length of lights that would be equal to the perimeter of the rectangular deck.

The perimeter of a rectangle is given as:

P = 2(L + B)

Hence, the length of lights he should buy is:

P = 2(799 + 245) = 2(1044)

P = 2088 inches

He should buy lights that are 2088 inches long.

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3 years ago

Find the length and width of a rectangle that has the given area and a minimum perimeter. Area: 162 square feet

Gnom [1K]

Answer:

The width and length of rectangle is 12.728 m

Step-by-step explanation:

Let the length of the rectangle = L

let the width of the rectangle = W

The subjective function is given by;

F(p) = 2(L + W)

F = 2L + 2W

Area of the rectangle is given by;

A = LW

LW = 162 ft²

L = 162 / W

Substitute in the value of L into subjective function;

$f = 2l + 2w\\\\f = 2(\frac{162}{w} )+2w\\\\f = \frac{324}{w} + 2w\\\\\frac{df}{dw} = \frac{-324}{w^2} +2\\\\$

Take the second derivative of the function, to check if it will given a minimum perimeter

$\frac{d^2f}{dw^2}= \frac{648}{w^3} \\\\Thus, \frac{d^2f}{dw^2}>0, \ since,\frac{648}{w^3} >0 \ (minimum \ function \ verified)$

Determine the critical points of the first derivative;

df/dw = 0

$\frac{-324}{w^2} +2 = 0\\\\-324 + 2w^2=0\\\\2w^2 = 324\\\\w^2 = \frac{324}{2} \\\\w^2 = 162\\\\w= \sqrt{162}\\\\w = 12.728 \ m$

L = 162 / 12.728

L = 12.728 m

Therefore, the width and length of rectangle is 12.728 m

3 0

2 years ago