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2 years ago

If x = -6, which inequality is true?

Mathematics

1 answer:

lakkis [162]2 years ago

8 0

Answer:

Step-by-step explanation:

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Carla plumbing charges $25 for a service call and $28 per hour, h, for labor for any repair. The total cost , t, for a repair ca

Ulleksa [173]

Answer:

It took 5 hours

Step-by-step explanation:

Because 28 times 5 is 140 plus 25 for the call is 165.

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3 years ago

How is the pattern changing to get from one term to the next? 55, 49, 43, 37, 31,...

ZanzabumX [31]

Answer:

Step-by-step explanation:

55-6=49

49-6=43

43-6=37

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3 years ago

0.346 x 10 to the second power x 10 = help

scZoUnD [109]

346
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3 years ago

Read 2 more answers

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

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3 years ago

The sum of two numbers is -10.5 , identify two negative addends that make the statement true

Brrunno [24]

PLUG IN TWO NEGATIVE NUMBERS

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3 years ago