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nadya68 [22]
3 years ago
12

In a lab experiment, 130 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to dou

ble every 8 hours. How many bacteria would there be after 24 hours, to the nearest whole number?
Mathematics
1 answer:
Scrat [10]3 years ago
4 0

Answer:

1040

Step-by-step explanation:

8 hours = 260

16 hours = 520

24 hours = 1040

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What number must you add to complete the square? x^2+14x=-7
viktelen [127]
To complete the square of a polynomial, use the term "(b / 2) ^ 2".

In this polynomial, the "b" term is 14.
Plug that in.

(14 / 2) ^ 2
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Can someone help ASAP I think Ik the answer but don’t wanna get wrong
Elden [556K]

Answer:

(4x+1)= 81

Step-by-step explanation:

4x+1= 81

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Looking at the top of tower A and base of tower B from points C and D, we find that ∠ACD = 60°, ∠ADC = 75° and ∠ADB = 30°. Let t
katrin2010 [14]

Answer:

\text{Exact: }AB=25\sqrt{6},\\\text{Rounded: }AB\approx 61.24

Step-by-step explanation:

We can use the Law of Sines to find segment AD, which happens to be a leg of \triangle ACD and the hypotenuse of \triangle ADB.

The Law of Sines states that the ratio of any angle of a triangle and its opposite side is maintained through the triangle:

\frac{a}{\sin \alpha}=\frac{b}{\sin \beta}=\frac{c}{\sin \gamma}

Since we're given the length of CD, we want to find the measure of the angle opposite to CD, which is \angle CAD. The sum of the interior angles in a triangle is equal to 180 degrees. Thus, we have:

\angle CAD+\angle ACD+\angle CDA=180^{\circ},\\\angle CAD+60^{\circ}+75^{\circ}=180^{\circ},\\\angle CAD=180^{\circ}-75^{\circ}-60^{\circ},\\\angle CAD=45^{\circ}

Now use this value in the Law of Sines to find AD:

\frac{AD}{\sin 60^{\circ}}=\frac{100}{\sin 45^{\circ}},\\\\AD=\sin 60^{\circ}\cdot \frac{100}{\sin 45^{\circ}}

Recall that \sin 45^{\circ}=\frac{\sqrt{2}}{2} and \sin 60^{\circ}=\frac{\sqrt{3}}{2}:

AD=\frac{\frac{\sqrt{3}}{2}\cdot 100}{\frac{\sqrt{2}}{2}},\\\\AD=\frac{50\sqrt{3}}{\frac{\sqrt{2}}{2}},\\\\AD=50\sqrt{3}\cdot \frac{2}{\sqrt{2}},\\\\AD=\frac{100\sqrt{3}}{\sqrt{2}}\cdot\frac{ \sqrt{2}}{\sqrt{2}}=\frac{100\sqrt{6}}{2}={50\sqrt{6}}

Now that we have the length of AD, we can find the length of AB. The right triangle \triangle ADB is a 30-60-90 triangle. In all 30-60-90 triangles, the side lengths are in the ratio x:x\sqrt{3}:2x, where x is the side opposite to the 30 degree angle and 2x is the length of the hypotenuse.

Since AD is the hypotenuse, it must represent 2x in this ratio and since AB is the side opposite to the 30 degree angle, it must represent x in this ratio (Derive from basic trig for a right triangle and \sin 30^{\circ}=\frac{1}{2}).

Therefore, AB must be exactly half of AD:

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3 0
3 years ago
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We are given that the dimensions are 4 in x 9 in. To get the smallest possible square, first let us find for the LCM of 4 and 9.

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We can actually see that 36 is the least common multiple.

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<span>36 inches by 36 inches</span>

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Alex_Xolod [135]

Answer:

<h2>5040</h2>

Step-by-step explanation:

<h3>multiply 35 by 144 which will give you your answer (lcm)</h3>
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