Circumference = 2(pi)r
Area = (pi)r^2
r = 5
5 * 2 = 10
Circumference = 10π
5 * 5 = 25
Area = 25π
Using 3.14 as pi substitute:
5 * 3.14 = 15.7
15.7 * 2 = 31.4
Circumference = 31.4
5 * 5 = 25
25 * 3.14 = 78.5
Area = 78.5
Answer: x = 3/80
Step-by-step explanation:
Answer:
We accept the null hypothesis and conclude that voltage for these networks is 232 V.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 232 V
Sample mean, 
= 231.5 V
Sample size, n = 66
Sample standard deviation, s = 2.19 V
Alpha, α = 0.05
First, we design the null and the alternate hypothesis
We use Two-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
We accept the null hypothesis and conclude that voltage for these networks is 232 V.
A)The y-intercept is 50 because when X=0, y=50. This shows that the car was moving at 50 mph as an initial speed.
B) in two hours (from 1 to 3) the speed increased by 4 miles per 2hours. (from 52 to 56). 4/2 = 2 mph, which is the average rate of change. This represents the amount of speed increased each hour.
C) y=2x+50, and y=60 in this case, so 60=2x+50
60=2x+50
-50 -50
-----------------
10=2x
5=x, so the domain is X<=5 (less than or equal to 5)
Answer:
10 bugs
Step-by-step explanation:
If last month the spider ate 8 bugs, and this month the spider ate 25% more bugs, we can calculate the amount of bugs the spider ate this month finding how much is 25% of 8 bugs, and them we sum this value to the 8 bugs it ate last month.
25% of 8 = 8 * 25 / 100 = 2
Now we know that the spider ate 2 more bugs, so the amount of bugs it ate this month is 8 + 2 = 10 bugs.
We can also solve this problem multiplying directly 8 by 1.25 (1.25 represents the 25% increase in the bug consumption):
8 * 1.25 = 10 bugs.
