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3 years ago

Need help answer fast please

Mathematics

1 answer:

Snowcat [4.5K]3 years ago

4 0

Answer:

a = 4

Step-by-step explanation:

Assuming you require to find the value of a

In a rhombus all the sides are congruent, thus

9a - 13 = 3a + 11 ( subtract 3a from both sides )

6a - 13 = 11 ( add 13 to both sides )

6a = 24 ( divide both sides by 6 )

a = 4

Then

XW = 9a - 13 = 9(4) - 13 = 36 - 13 = 23

Thus the sides of the rhombus are 23 units

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5(2+c)=45+5c no solution

kolbaska11 [484]

Answer:

Step-by-step explanation:

You have to start out with the distributive property 5 times 2 times c is 10+5c; now you have to subtract 5c on both sides in the upside down T chart, now its 10=45+c and your answer will be c=4.5.

8 0

3 years ago

Which sequence follows the rule 2n + 6, where n represents the position of a term in a sequence? 6, 8, 12, 18, . . . 6, 12, 18,

melamori03 [73]

ANSWER

8, 10, 12, 14, . . .

EXPLANATION

The given rule for the sequence is :

f(n)=2n+6

The domain for a sequence is the set of natural numbers.

When n=1,

f(1)=2(1)+6=8

When n=2,

f(2)=2(2)+6=10

When n=3,

f(3)=2(3)+6=12

When n=4,

f(4)=2(4)+6=14

Therefore the sequence that follows the given rule is

8, 10, 12, 14, . . .

8 0

3 years ago

Write 0.088 as a fraction in simplest form.

zhenek [66]

11/25

88/1000
Divide each by 8
11. Times 8
125 times 8

7 0

3 years ago

If A and B are mutually exclusive events, then P(A or B) = P(A) + P(B).

Korolek [52]

Answer:

P(A or B) = 25%

Step-by-step explanation:

P(A and B) = 30%

P(A) = 40%

P(B) = 15%

Apply given formula:

P(A or B) = P(A) + P(B) - P(AB)

= 40%+15+-30%

= 25%

8 0

3 years ago

fatima claims that the distribution of u is uniform with a median of 0.4 field goal percentage. is fatima’s claim supported by t

Amanda [17]

Fatima's claim is not supported by the table because, the distribution is skewed right, with a median of 0.4 field goal advantage.

From the table, the median position is calculated as:

$\mathbf{Median = \frac{1}{5} th}$

$\mathbf{Median = 0.2\ nd }$

The 0.2nd data falls in the 0.4 field goal category.

So, the median element is:

$\mathbf{Median = 0.4}$

However, the distribution of the table are concentrated on the left.

This means that, the distribution is not uniform, instead it is skewed right.

A uniform distribution has a skewness of 0.

Hence, Fatima's claim is not supported by the table