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3 years ago

There are TWO questions!! Please help me!! Thank you loves!! <3

Mathematics

1 answer:

Naily [24]3 years ago

7 0

Rotation is a rigid transformation. It changes neither lengths nor angle measures.

1. B. 52 degrees

2. B. 18 in.

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Find the value using identities (302)3

Arlecino [84]

Answer:

108,000,934

1.08934×10^8

Step-by-step explanation:

(302)^3

(a+b)^3

(a+b)^3==a^3+3a^2b+3ab^2+b^3

(300+2)

(300)^3+3(300^2+2)+3(300+2^2)+2^3

27,000,000+81,000,002+8+924

108,000,002+8+924

108,000,934 or 1.08934×10^8

8 0

3 years ago

Analyze a graph In Exercise,analyze and sketch the graph of the function.Label any relative extrema, points of inflation,and asy

FinnZ [79.3K]

Answer:

Step-by-step explanation:

Given is a function of x

$f(x) = xe^{-x}$

When y=0 we get x=0 and infinity

Hence x intercept is 0 and one asymptote is x axis.

When x=0 , y =0

$f'(x) = e^{-x}(-x+1)$

$f''(x) = e^{-x}(x-1-1)$

Maxima at x=1, and point of inflection is at x=2

Increasing upto x=1 and then decreases

Graph is enclosed

6 0

3 years ago

How to describe the behavior of the f (x) from the left and from the right of vertical asymptote

Naddik [55]

Here you go, hope this kinda helps you out :)

8 0

3 years ago

The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

3 years ago

Find the iqr of 4 5 6 8 9 10 11 12

77julia77 [94]

Answer:

The interquartile range is 5.

Step-by-step explanation:

Ah, a throwback to interquartile range... let me help :)

4,5,6,8,9,10,11,12

First, you need to know how to use the IQR. The interquartile range is basically known as the process of subtracting the upper quartile and the lower quartile of a set of data. The lower quartile should be written as Q1, and the upper quartile would be labeled as Q3. This would make the midpoint (median) data set Q2, and the highest possible point would be labeled Q4. Next, you have to always understand what you are looking at. For example, let's split the set 5,6,7,8,9,10,11,12 into groups. 5 and 6 would be Q1, 7 and 8 would be Q2, 9 and 10 would be Q3, and last but not least, 11 and 12 would be labeled as Q4. Now take Q1 and subtract it from Q3 and that is how you get your IQR.

3 0

3 years ago

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