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miskamm [114]
3 years ago
10

Help with math thanks so much!!!!

Mathematics
1 answer:
KatRina [158]3 years ago
6 0

Answer:

0.2

Step-by-step explanation:

14/10÷x=7

14/10=7x

1.4±7=x

x=0.2

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To prepare for a bake-off, Chad used 520 grams of flour each day for 2 weeks. How many kilograms did Chad use in those 2 weeks?
Shalnov [3]

Answer:

7.280 k

Step-by-step explanation:

Given that  1 g = 0.001 k

If he uses 520 grams of flour each day for 2 weeks, since there are 7 days in a week, the total weight of flour used in two weeks

= 520 g * 2 * 7

= 7280 g

In kilograms

Since

1 g = 0.001 k

7280 g = 7280/1 * 0.001 k

= 7.280 k

3 0
3 years ago
The ratio of girls to boys in jame’s chorus is 2 to 4. If there are 25 girls in her chorus, how many boys are there ?
Brilliant_brown [7]

Answer:

There are 50 boys

Step-by-step explanation:

girls to boys - 2:4

so 25x2=50

3 0
3 years ago
Have you ever been swimming in a pool, and your eyes were red when you get out? This means the chemicals in the pool were not ad
soldier1979 [14.2K]

pH = f(x) = -log₁₀x

1. Graphs

I used Excel to calculate the pH values and draw the graphs (see the Figure).

f(x) and f(x) +1 are plotted against the left-hand axis, while f(x+ 1) is plotted against the expanded right-hand axis.

The points at which pH = 0 and pH = 1 are indicated by the large red dots.

2. x = 0.5

When x = 0.5, pH ≈0.30. The point is indicated by the red diamond.

3. Transformations

(a) ƒ(x) = -log(x) + 1

This function has no y-intercept, because log(0) is undefined.

(b) ƒ(x +1) = -log(x + 1)

f(0) = -log(0 + 1) = -log(1) = 0

This function has a y-intercept at (0,0).

hope this helps please mark me brainliest!

3 0
3 years ago
Simplify 4+3(7+4 x 2)-100<br> Solve this
siniylev [52]
4+3(7+4 x 2)-100
4+3(7+8)-100
4+3(15)-100
4+45-100=
-51
8 0
3 years ago
Read 2 more answers
How many gallons of a 80% antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antif
konstantin123 [22]

440 gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get a mixture that is 70% antifreeze

<em><u>Solution:</u></em>

Let "x" be the gallons of 80 % antifreeze added

Therefore, "x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze

Final mixture is x + 80

Therefore, we can frame a equation as:

"x" gallons of 80 % antifreeze solution must be mixed with 80 gallons of 15% antifreeze to get (x + 80) gallons of 70 % antifreeze

Thus, we get,

x gallons of 80 % + 80 gallons of 15 % = (x + 80) gallons of 70 %

x \times \frac{80}{100} + 80 \times \frac{15}{100} = (x+80) \times \frac{70}{100}\\\\0.8x + 80 \times 0.15 = (x+80) \times 0.7\\\\0.8x+12 = 0.7x+56\\\\0.8x-0.7x=56-12\\\\0.1x = 44\\\\x = \frac{44}{0.1}\\\\x = 440

Thus 440 gallons of 80 % antifreeze solution must be mixed

4 0
3 years ago
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