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3 years ago

Can someone help me with this it is for mathh.

Mathematics

1 answer:

lapo4ka [179]3 years ago

8 0

Answer: it would be P=4n

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Subtract. -8- 21= would -13 be the answer

FrozenT [24]

$-8-21=-29$

6 0

3 years ago

|2x+3|-8= -3<br> EXPLAIN why this equation has 2 solutions<br> instead of no solution.

Nimfa-mama [501]

Answer:

This has 2 solutions

Step-by-step explanation:

This question has 2 solutions because the answers can be x=1 and x=-4 because 5-8=-3 and you can get 5 with a absolute value and 5-8=-3

5 0

3 years ago

Describe the set of all positive integers from 10 to 15 using the descriptive method

True [87]

Given:

The set of all positive integers from 10 to 15.

To find:

The given set by using the descriptive method.

Solution:

The positive integers are 1, 2, 3, 4,... .

The positive integers from 10 to 15 are 10, 11, 12, 13, 14, 15.

So, the given set has 5 elements 10, 11, 12, 13, 14, 15.

Using the descriptive method, the given set is defined as "The set of all positive integers greater than or equal to 10 and less than or equal to 15".

Therefore, the set of all positive integers greater than or equal to 10 and less than or equal to 15.

3 0

2 years ago

what is an equation in slope intercept form for the line that passes through the points (1,-3) and (3,1)

Ede4ka [16]

Y=2x-5.
I found the slope using the formula m=y2-y1/x2-x1.
m=-3-1/1-3=-4/-2=2.

I used (3,1) (only use one point, your choice) to find out b. 3=x, 1=y.
y=mx+b is the formula for slope intercept equations, so I plugged in the x and y.
1=2(3)+b; 1=6+b, subtract 6 on both sides and get -5=b.
I used the information to get y=2x-5.
Hope this isn’t too confusing! :)

6 0

3 years ago

One ordered pair (a,b) satisfies the two equations ab^4 = 384 and a^2 b^5 = 4608. What is the value of a in this ordered pair?

Alekssandra [29.7K]

Answer: a = 3∛2

<u>Step-by-step explanation:</u>

ab⁴ = 384 --> a = 384/b⁴

Substitute a = 384/b⁴ into the second equation to solve for "b".

a²b⁵ = 4608

$\bigg(\dfrac{384}{b^4}\bigg)^2\cdot b^5=4608\\\\\\\dfrac{147,456b^5}{b^8}=4608\\\\\\\dfrac{147,456}{b^3}=4608\\\\\\\dfrac{147,456}{4608}=b^3\\\\\\32=b^3\\\\\\\sqrt[3]{32} =b\\\\\\2\sqrt[3]{4} =b$

Substitute b = 2∛4 into the first equation to solve for "a".

ab⁴ = 384

a(2∛4)⁴ = 384

a = 384/(2∛4)⁴

a = 24/4∛4

= 6/∛4

= 6(∛2)/2

= 3∛2

5 0

3 years ago