2(5n-2)=4(n+2)
10n-4=4n+8
6n-4=8
6n=12
n=2
Answer:
number of ways = 720
Step-by-step explanation:
The number of ways six people sit in a six-passenger car is given by the number of permutations of 6 elements in 6 different positions ( seats), then
number of ways = number of permutations of 6 elements = 6! = 6 * 5 * 4 *3 * 2 * 1 = 720
Since the first person that sits can be on any of the seats , but then the second person that sits can choose any of 5 seats (since the first person had already occupied one) , the third can choose 4 ... and so on.
Answer:
10 -> 14
15-> 19
20-> 24
25-> 29
Step-by-step explanation:
Add 4 each time
That's the uniion of sets B and C
that means inclde all the values of both sets (not meaning the ones common to both sets)
so that would include a,b,c,d, 0,a,2,b
a and b repeat so list them only once
that would be {a,b,c,d,0,2}
answer is 4th option
Answer: 108 tickets must be sold to cover the cost.
123 tickets must be sold to make a profit of approximately $980.68
Step-by-step explanation:
Just divide 859.32 from 8 to find out how many tickets must be sold to cover the cost. Same for part b.
Hope this helps!