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erastovalidia [21]
3 years ago
9

A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random

sample of 36 bins, the sample mean amount was 49.01 pounds and the sample standard deviation was 3.7 pounds. Conduct the appropriate hypothesis test using a 0.05 level of significance.What are the appropriate null and alternative hypotheses?A. H0: x = 50 versus Ha: x ? 50B. H0: ? = 50 versus Ha: ? ? 50 C. H0: ? = 50 versus Ha: ? < 50D. H0: ? = 50 versus Ha: ? > 50
Mathematics
1 answer:
frez [133]3 years ago
6 0

Answer: H_0 : \mu=50\\\\ H_1 : \mu\neq50

Step-by-step explanation:

An null hypothesis (H_0) is a statement of equality which shows that there is no statistical difference between the groups being tested.

An alternative hypothesis  (H_1) is a statement of inequality which shows that there is statistical difference between the groups being tested.

Let \mu be the population mean amount of garbage per bin .

Given : A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50.

i.e. \mu\neq 50 → Alternative

Thus , the appropriate null and alternative hypotheses :

H_0 : \mu=50\\\\ H_1 : \mu\neq50

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Answer:

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b) p_v =P(z>1.308)=0.0954  

Step-by-step explanation:

Data given and notation

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Concepts and formulas to use  

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Alternative hypothesis:p > 0.2  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

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The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

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Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.239 -0.2}{\sqrt{\frac{0.2(1-0.2)}{180}}}=1.308  

Part b: Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z>1.308)=0.0954  

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