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Rashid [163]
3 years ago
13

How do you do this I have no idea

Mathematics
2 answers:
Effectus [21]3 years ago
3 0
I cannot see that properly.
ICE Princess25 [194]3 years ago
3 0
First you start with labeling them. That makes it easier to place numbers where they need to be
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Quotient 2 divided by 2 3
BARSIC [14]

Answer: 11.5

Step-by-step explanation:

7 0
2 years ago
8(10)2y = 7200<br> What the answer
garik1379 [7]

Answer:

y = 45

Explanation:

(8)(10)(2)y = 7200

[ Simplify both sides of the equation ]

160y = 7200

[ Divide both sides by 160 ]

160y / 160 = 7200 / 160

y = 45

Check:

8(10)2(45) = 7200

7 0
2 years ago
Solve using test intervals |x 1|&gt; or equal to 4
insens350 [35]
<span><span>Solve <span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120 </span></span>><span><span> 0</span>. </span></span><span>First, I factor to find the zeroes:<span><span>x5 + 3x4 – 23x3 – 51x2 + 94x + 120</span><span>= (x + 5)(x + 3)(x + 1)(x – 2)(x – 4) = 0</span></span><span>...so </span><span>x = –5, –3, –1, 2,</span><span> and </span>4<span> are the zeroes of this polynomial. (Review how to </span>solve polynomials, if you're not sure how to get this solution.)<span>To solve by the Test-Point Method, I would pick a sample point in each interval, the intervals being </span>(negative infinity, –5)<span>, </span>(–5, –3)<span>, </span>(–3, –1)<span>, </span>(–1, 2)<span>, </span>(2, 4)<span>, and </span>(4, positive infinity). As you can see, if your polynomial or rational function has many factors, the Test-Point Method can become quite time-consuming.<span>To solve by the Factor Method, I would solve each factor for its positivity: </span><span>x + 5 > 0</span><span> for </span><span>x > –5</span>;<span>x + 3 > 0</span><span> for </span><span>x > –3</span><span>; </span><span>x + 1 > 0</span><span> for </span><span>x > –1</span><span>; </span><span>x – 2 > 0</span><span> for </span><span>x > 2</span><span>; and </span><span>x – 4 > 0</span><span> for </span><span>x > 4</span>. Then I draw the grid:...and fill it in:...and solve:<span>Then the solution (remembering to include the endpoints, because this is an "or equal to" inequality) is the set of </span>x-values in the intervals<span> [–5, –3]<span>, </span>[–1, 2]<span>, and </span>[4, positive infinity]</span>. </span>

As you can see, if your polynomial or rational function has many factors, the Factor Method can be much faster.

<span>
</span>
4 0
3 years ago
Expand and simplify <br> 4(2x+3)+ 4(3x+2)
stepladder [879]

Answer:

20x + 20

Step-by-step explanation:

4(2x+3)+ 4(3x+2)

Expand the brackets.

8x + 12 + 12x + 8

Now simplify.

20x + 20

6 0
2 years ago
If X || Y and Y || Z, then _____<br><br> A) A || B<br> B) X || Z<br> C) X⊥A<br> D) A⊥Z
iris [78.8K]

Answer:

B) X || Z

Step-by-step explanation:

Hope it helps you in your learning process.

5 0
2 years ago
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