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sveticcg [70]
3 years ago
11

Abby can paint 1/3 of her room in 30 minutes.at what rate could she paint her room?

Mathematics
2 answers:
BigorU [14]3 years ago
8 0

Answer:

To paint the room it would take 90 minutes, the rate is that she can paint 1/30 of her room each minute

Step-by-step explanation:

MatroZZZ [7]3 years ago
3 0

Answer:

3mper min

Step-by-step explanation:

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Plz help i'll mark brainliest In the box, type the number that will complete the sentence correctly. Use a hyphen to show a mixe
OverLord2011 [107]

Answer: -2 1/4

Step-by-step explanation: I think that's right but you can try it.

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4/49 times 7/13 thank you
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0.04395604395

Step-by-step explanation:

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3,842.58 rounded to the nearest tenth
Nataliya [291]
The tenths place is where the 5 is
To round, look at the number before it which is a 8
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3 years ago
Determine whether the set of vectors is orthonormal. If the set is only​ orthogonal, normalize the vectors to produce an orthono
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Answer:

(i) See attached image file

(ii) Option A

Step-by-step explanation:

See attached image file

6 0
3 years ago
Assume the random variable X is normally distributed with mean 53 and standard deviation of 6. Find the 9th percentile
satela [25.4K]

Answer:

<em>The 9th percentile of X is 44.96</em>

Step-by-step explanation:

<u>Percentiles for a Normal Distribution</u>

The standard normal distribution can be used for computing percentiles. For example, the median is the 50th percentile being the center value, the first quartile is the 25th percentile, and so on.

To compute percentiles of a normal distribution we can use the formula

X=\mu+z\sigma

Where \mu is the mean, \sigma is the standard deviation of the variable X, and z is the z-score value from the standard tables

The value of X can also be directly obtained from digital tables included in math packages and tools like Excel.

The Excel NORM.INV Function calculates the inverse of the cumulative Normal Distribution Function for a given value of p, \mu and \sigma.

We'll use the values

p=9\%=0.09,\ \mu=53, \ \sigma=6

NORM.INV(0.09,53,6) results in 44.96 which means the 9th percentile of X is 44.96

We could have used the standard normal distribution, which only needs the value of p

NORM.S.INV( 0.09 )=-1.34

That is the value of z, we now apply the formula

X=\mu+z\sigma

X=53+(-1.34)\cdot 6=44.96

We get the very same result as before

6 0
3 years ago
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