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2 years ago

Help :( ima link it........

Mathematics

1 answer:

suter [353]2 years ago

8 0

Answer:

Step-by-step explanation:

he is DIVIDING it among his children so the equation will have division

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Find the measure of the arc or angle indicated.

xenn [34]

For each problem, use the inscribed angle theorem.

19.

$45^\circ=\dfrac12m\widehat{QR}\implies m\widehat{QR}=90^\circ$

20.

$95^\circ=\dfrac12m\widehat{ABC}\implies m\widehat{ABC}=190^\circ$

21.

$49^\circ=\dfrac12m\widehat{LR}\implies m\widehat{LR}=98^\circ$

LN is a diameter, so arc LN has measure 180º, and so

$m\widehat{LR}+m\widehat{RN}=m\widehat{LN}=180^\circ\implies m\widehat{RN}=82^\circ$

7 0

3 years ago

Ok, I am so sorry ,I rlly don't understand any of these things , can y'all help me with

melomori [17]

Answer:

x is 2.88 which can be rounded up to 2.9

Step-by-step explanation:

Subtract 2/3x from 5x.

Add 1/2 to 12.

Simplify and put into calculator (y=) to double check.

3 0

3 years ago

Solve for x 78.2+0.5x=287

diamong [38]

1. move 78.2 over to the over side. This will give you 287-78.2.

2. when you have .5x = 208.8, divide both sides by .5

3. this should give you x= 417.6

4. make sure to check your work by plugging you answer back into x.

4 0

3 years ago

Read 2 more answers

What is the least common multiple of 8 and 12? 24 48 96

Anna007 [38]

Answer:

The least common multiple of 8 and 12 is 24

Explanation:

Find and list the multiples each number until the first common multiple is found.

This is the lowest common multiple .

Multiples of 8

8, 16, 24, 32,40

Multiples of 12

12,24, 36,48

Therefore,

LCM of 8 and 12 is 24

3 0

3 years ago

Read 2 more answers

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3>Solution:</h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

Ratio for the volumes of two cylinders

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago