Answer:
iwill edit
Step-by-step explanation:
= 18 cm^3
V = Bh where B is the area of the base, which is the triangular face
B = 1/2 (4*3) = 6
V = 6* 3
V = 18 cm^3
1.49103082= 1.49
B'=U-B={q, r, s, t, u, V, W, x, y, z}-{q, s, y, z}={r,t, u, V, W, x, y}
A'=U-A={q, r, s, t, u, V, W, x, y, z}-{q, s, u, w, y}={r,t,v,w,x,z}
B'UC={r,t, u, V,W, x, y}U{v, w, x, y, z).={{r,t, u, V,W, x, y,z}
(B'U C) U A'={{r,t, u, V,W, x,y,z}U{r,t,v,w,x,z}={{r,t, u, V,W, x,y,z}
