Answer: ![\bold{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cbold%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
<u>Step-by-step explanation:</u>
![\dfrac{1}{2}\sqrt[4]{32} =\dfrac{1}{2}\sqrt[4]{2\cdot 2\cdot 2\cdot 2\cdot 2}=\dfrac{1}{2}\cdot 2\sqrt[4]{2}=\boxed{\sqrt[4]{2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B32%7D%20%3D%5Cdfrac%7B1%7D%7B2%7D%5Csqrt%5B4%5D%7B2%5Ccdot%202%5Ccdot%202%5Ccdot%202%5Ccdot%202%7D%3D%5Cdfrac%7B1%7D%7B2%7D%5Ccdot%202%5Csqrt%5B4%5D%7B2%7D%3D%5Cboxed%7B%5Csqrt%5B4%5D%7B2%7D%20%7D)
Answer:
Hey there!
We have an=a1(r^n-1), which is the formula for a geometric sequence.
The common ratio is 3, and 2 is the 1st term.
Thus, we have a1=2(3)^(n-1)
Hope this helps :)
Answer:
4 ft
7.2 ft
20 ft
Step-by-step explanation:
When the balloon is shot, x = 0.
y = -0.05(0)² + 0.8(0) + 4
y = 4
The balloon reaches the highest point at the vertex of the parabola.
x = -b / 2a
x = -0.8 / (2 × -0.05)
x = 8
y = -0.05(8)² + 0.8(8) + 4
y = 7.2
When the balloon lands, y = 0.
0 = -0.05x² + 0.8x + 4
0 = x² − 16x − 80
0 = (x + 4) (x − 20)
x = -4 or 20
Since x > 0, x = 20.

1) Iteration means a repetition of a rule.
a)
Considering that we have the following data:
Rate of increase: 5% per year
-
2) Then we can write out the following:

Plugging into n, the number of years we'll have:
Profits: $30,000 1st year
P: $31.500 2nd year
$33075 3rd year
(...) (...)
b) Since we want to know the predicted profit 15 years from the first year, then we can plug for that:

Note that we have plugged into n, n=15 years. Since the first year was $30,000 the profits.
your answer would be x=21/13
When the logs have the same base: logb(f(x)) = logb(g(x)) --> f(x) g(x)
if im correct please mark brainliest :)