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Anna007 [38]
3 years ago
9

Helppppppp pleaseeee

Mathematics
2 answers:
devlian [24]3 years ago
8 0

Answer:

y= 1/3x + 2

Step-by-step explanation:

I used desmos

Nat2105 [25]3 years ago
3 0

Answer:

2

Step-by-step explanation:

The Y intercept is where x is = to zero.

If x is zero that is one section of the chart back.

so 1 would be subtracted from Y.

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your method is correct

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How to differenciate natural,whole,integers,rational,irrational numbers and real numbers sets from -12 to 49 and draw numbers li
slavikrds [6]

Answer:

Step-by-step explanation:

Natural Numbers :

These are numbers used for counting, they are the numbers on a number line. From -12 to 49, the natural numbers are 1, 2, 3, ..., 49.

Whole Numbers:

These are numbers that can be written without havin to write in fractions. They are 0, 1, 2, ..., 49.

Rational Numbers:

These are numbers that can be expressed as fractions.

Irrational numbers :

These are numbers that cannot be expressed as fractions.

Real Numbers:

These are numbers that can be used to measure quantities, they include negative, positive numbers and zero. From -12 to 49, all the numbers are real.

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From 7 to 49, the numbers divisible by 7 are 7, 14, 21, 28, 35, 42, and 49.

Only 7 is prime.

3 0
3 years ago
Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

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3 years ago
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