<h3>Answer:</h3>
a, e
<h3>Explanation:</h3>
If any of the terms has a variable with an exponent other than 1 or 0, or has a sum of variable exponents other than 1, the term is non-linear and the relation is not a linear relation.
a: the term xy has a sum of exponents of 1+1=2, so is not a linear term.
e: the term x² has an exponent other than 0 or 1, so is not a linear term.
In the attached graph, the non-linear relations are shown graphed in black. The remaining relations are all linear.
_____
<em>Comment on linear function</em>
By one definition, a linear function is one that is of the form
... f(x) = ax + b
Here, an equation such as <em>y = x + 2y</em> can be put in that form, but it is <em>not</em> in that form as presented. Yes, the graph is of a straight line, but you would have a hard time identifying independent and dependent variables from the equation as given.
Just divide $100 by 5. 100 divided by 5 = $20 each.
For this case, the first thing you should do is define a variable.
We have then:
g: unknown number.
We now write the expression in algebraic form.
the sum of 5 and a number:
g + 5
Answer:
An expression that means the sum of 5 and a number is:
C. g + 5
<h3>Answer: y = (3/2)x + 0</h3>
This is the same as y = (3/2)x
=============================================================
Work Shown:
Find the slope of the line through (x1,y1) = (-2,-3) and (x2,y2) = (2,3)
m = (y2 - y1)/(x2 - x1)
m = (3 - (-3))/(2 - (-2))
m = (3 + 3)/(2 + 2)
m = 6/4
m = 3/2
The slope is the fraction 3/2. This is going to be in front of the x, or to the left of the x.
----------
Plug m = 3/2 and (x1,y1) = (-2,-3) into the point slope formula. Solve for y.
y - y1 = m(x - x1)
y - (-3) = (3/2)(x - (-2))
y + 3 = (3/2)(x + 2)
y + 3 = (3/2)x + (3/2)(2)
y + 3 = (3/2)*x + 3
y + 3 - 3 = (3/2)*x + 3 - 3
y = (3/2)x + 0
The y intercept is zero. This matches up with the fact the graph crosses the y axis at y = 0.
Step-by-step explanation:
Tip 1) Always Start from the More Complex Side.
Tip 2) Express everything into Sine and Cosine.
Tip 3) Combine Terms into a Single Fraction.
Tip 4) Use Pythagorean Identities to transform between sin²x and cos²x.
Tip 5) Know when to Apply Double Angle Formula (DAF)
I am also from nepal...very happy to see you..
