Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
11. Similar 1/2
12. Similar 2
13. no
14. no
15. No, they are not congruent because rectangles do not have equal sides, so the length of one triangle could be longer than the other and the width ozone can be shorter than the other.
16. Yes
The answer is B.)
The answers are using the distributive property. The distributive property multiplies both the numbers inside the parenthesis by the number that's on the outside of the parenthesis.
6x3 = 18, 6x4x=24x.
Hope this helps :) work hard!
Answer:
-11
Step-by-step explanation:
Triangle ABC
SO,
AB = AC +BC
x + 8 = 2x -5 + (BD + DC)
x + 8 = 2x-5 + 10 +14
x + 8 = 2x + 19
2x - x = -19 + 8
x = -11
A for both of them add all the numbers up and divide by the amount of numbers to get your iQR but A is right for both
