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Deffense [45]
3 years ago
15

Mack the bug starts at (0,0) at noon and each minute moves one unit right or one unit up. He is trying to get to the point (5,7)

. However, at (2,3) there is a spider that will eat him if he goes through that point. In how many ways can Mack reach (5,7) ?
Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
4 0
<span>This is a very nice counting question. Suggestion / Hint: Count how many ways he can get from (0,0) to (5,7) by going through the point (2,3). Then subtract that from ALL POSSIBLE ways he can get from (0,0) to (5,7). Hint for the hint: How many ways he can get from (0,0) to (5,7) by going through the point (2,3)? Well, that's the SUM of how many ways he can get from (0,0) to (2,3) and how many ways he get get from (2,3) to (5,7). Hope this helps! :)</span>
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1. If a - b = 4 and a + b = 12, what is the<br> value of a?
Nezavi [6.7K]

I think this is what you are looking for:

=−12

a

b

=

−

12

+=4

a

+

b

=

4

(+)2=42

(

a

+

b

)

2

=

4

2

2+2+2=16

a

2

+

b

2

+

2

a

b

=

16

∴2+2=16+2×12=40

∴

a

2

+

b

2

=

16

+

2

×

12

=

40

Now, (−)2=2+2−2=40+2×12=64

(

a

−

b

)

2

=

a

2

+

b

2

−

2

a

b

=

40

+

2

×

12

=

64

∴(−)=64‾‾‾√=±8

∴

(

a

−

b

)

=

64

=

±

8

So, 2−2=(+)(−)

a

2

−

b

2

=

(

a

+

b

)

(

a

−

b

)

2−2=(4)(±8)=±32

a

2

−

b

2

=

(

4

)

(

±

8

)

=

±

32

Hope that helps and sorry if it is confusing!

4 0
2 years ago
Read 2 more answers
Estimate. Divide using the standard algor ithm and check.
KatRina [158]

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8 0
3 years ago
Prove that an integer consisting of 3n ones is divisible by 3n (e.g. 111 is divisible by 3, 111,111,111 is divisible by 9, etc.)
mote1985 [20]

For proof of 3 divisibility, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

<h3>Integers divisible by 3</h3>

The proof for divisibility of 3 implies that an integer is divisible by 3 if the sum of the digits is a multiple of 3.

<h3>Proof for the divisibility</h3>

111 = 1 + 1 + 1 = 3  (the sum is multiple of 3 = 3 x 1)  (111/3 = 37)

222 = 2 + 2 + 2 = 6 (the sum is multiple of 3 = 3 x 2)  (222/3 = 74)

213 = 2 + 1 + 3 = 6 ( (the sum is multiple of 3 = 3 x 2)  (213/3 = 71)

27 = 2 + 7 = 9  (the sum is multiple of 3 = 3 x 3)  (27/3 = 9)

Thus, abc is a divisible by 3 if the sum of abc (a + b + c) is a multiple of 3.

Learn more about divisibility here: brainly.com/question/9462805

#SPJ1

5 0
2 years ago
Manuel created a factor tree and wrote the prime factorization of 60 shown below.
bagirrra123 [75]

Answer:

The second one or B- "He did not find the prime factors of 4."

Step-by-step explanation:

I got it right on Edge2020

7 0
2 years ago
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Which weighs more a 20 pound turkey or 320 ounces of turkey stuffing? How do you know?
Keith_Richards [23]

Answer:

They are equal

Step-by-step explanation:

320 oz is 20 pounds:))

7 0
2 years ago
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