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Pani-rosa [81]
3 years ago
14

How do I solve x^2+11x+28=0

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
3 0
Are you factoring ?

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given a standard deck of 52 cards what is the probability of drawing a face card of any suit or a red 6 a 4/13 b 1/4 c 3/13 d 7/
Mademuasel [1]

Answer:

Choice D 7/26

Step-by-step explanation:

So first let's count how many face cards there are. We have a Jack, a Queen, and a King in all of the 4 sets of cards. This knowledge tells us that we have 12 face cards out of the 52 cards.  Then, we have 2 red sixes in the game.  These come from the 6 of hearts and the 6 of diamonds.  This makes the new total of the cards we want to draw 12+2=14. Then we now have the fraction 14/52.  After simplifying we get the answer 7/26 is our probability (choice D)

5 0
3 years ago
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You are a store clerk assigned to stack notebooks in a box for shipment. Each notebook is 29 centimeters long , 21.5 centimeters
coldgirl [10]

Answer:

what is the question???

6 0
3 years ago
Solve for t.<br><br> 5 + 2t = 7
frutty [35]

Answer:

t=1

Step-by-step explanation:

4 0
3 years ago
HELP ME PLS ITS PYTHAGOREAN THEOREM
tensa zangetsu [6.8K]

Answer:

82

Step-by-step explanation:

You are looking for the hypotenuse.

c = ?

a = 80

b = 18

c^2 = a^2 + b^2

c^2 = 18^2 + 80^2

c^2 = 324 + 6400

c^2 = 6724

sqrt(c^2) = sqrt(6724)

c = 82 inches

5 0
4 years ago
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The diagram shows 5cm×5cm×5cm cube calculate the length of the diagonal ab
mario62 [17]

Answer:

AB = 5\sqrt{3} cm

Step-by-step explanation:

As we can see from the figure, BCDE is a square with each corner equal to 90°.

So that, BDE is a right triangle with corner BED equal to 90°

As BDE is a right triangle, according to Pythagoras theorem, we have:

         BD^{2} = BE^{2} +ED^{2} = 5^{2} + 5^{2} = 25 + 25 = 50cm

As the diagram s the cube, so that it can be seen that AD is perpendicular to the surface BCDE

=> AD is perpendicular to BD

=> ADB is the right triangle with corner ADB equal to 90°.

As ADB is the right triangle, ccording to Pythagoras theorem, we have:

AB^{2} =AD^{2} + BD^{2} = 5^{2} +50 = 25 +50 = 75 cm

=> AB = \sqrt{75}  = 5\sqrt{3} cm

Conclusion: AB = 5\sqrt{3}cm

4 0
3 years ago
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