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2 years ago

6

I need help this is easy tho!

2 answers:

tamaranim1 [39]2 years ago

8 0

Answer:

it is true

it's a quadralateral

Goshia [24]2 years ago

4 0

The answer is false

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Here is an expression.

sp2606 [1]

Answer:

b

Step-by-step explanation:

is the situation could the expression model.

6 0

1 year ago

A problem states: "There are 2 more horses than cows in a field. There are 15 animals in the field in all. How many horses are t

mash [69]

Let h = the number of horses in the field
Let c = number of cows in the field

There are 2 more horses than cows in the field. Therefore
h = c + 2
or
c = h - 2 (1)

There are 15 animals in the field. Therefore
h + c = 15 (2)

Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15

Answer:
The correct equation is
2h - 2 = 15

4 0

2 years ago

Read 2 more answers

Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5). Describe the ste

olga_2 [115]

1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.

2. So f(x)= $(x-a)^{3}$

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

$f(x)=b(x-a)^{3}$

4. Now, f(0)=-5 so $-5=f(0)=b(0-a)^{3}=b(-a) ^{3}=-ba ^{3}$

$-5=-ba ^{3}$

$5=ba ^{3}$

$b= \frac{5}{ a^{3} }$

5. the function is $f(x)=\frac{5}{ a^{3} }(x-a)^{3}$ where a can be any real number except 0

7 0

3 years ago

Read 2 more answers

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

A truck that is 10 ft. by 12 ft. by 8 ft. carries cube shaped boxes that have a

dedylja [7]

Answer:

284.4

Step-by-step explanation:

Divide all numbers by 1.5. example: (10)1.5(12)1.5(81.5= 284.444444 but I rounded it to 284. You're welcome

4 0

2 years ago